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write the Ka and Kb expressions for the ionization of HX and X respectively in a general nonaqueous solvent?

2006-09-23 03:22:56 · 2 answers · asked by joy 1 in Science & Mathematics ➔ Chemistry

2 answers

ka=[H+][X-]/[HX]

kb=[OH-][HX]/[X-]

2006-09-23 03:44:49 · answer #1 · answered by Greg G 5 · 0⤊ 0⤋

Hey now! Back up a bit. What the hey?

2006-09-23 03:24:43 · answer #2 · answered by Anonymous · 0⤊ 0⤋

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