Help with numberlines...?

Question

If you were given a problem that said,

x > -2

Then when you graph it on a number line would you just cirlcle -2 or do you have to find x? And if you have to find x how do you do it?

Thankyou all who helped me I really do understand it now. But now what I don't understand is how to solve an inequality. For example,

9 + a > 11

Answer 1

9 + a > 11

9 is being added to the left side...
You do the opposite...
Subtract 9 from the left side...

11 - 9 = 2
You have the equation equality a > 11

Your number goes in the middle of the number line...

This is how you read your inequalities...

EXAMPLES
a > 11 = a is greater than 11...
a < 11 = a is less than 11...
a < -11 = a is less than -11...

Say that out loud and then you'll know how to graph it...

For this problem, a > 11, you'll have an open circle on the eleven shaded to the right and then you'll need to make the right arrow big and fat because that line goes on forever...

FYI...

If you're in this situation...

-2X < 4, you divide each side by a -2. Whenever you divide by a negative number and it's an inequality, you change the sign. Now your inequality is X > -2...

E-mail me...

Answer 2

As the person who answered before me said, x is all numbers greater than -2, however, to answer your question entirely, take a look at this image : -
http://library.thinkquest.org/20991/media/alg_inequal.gif
That is an example of x < 4, i.e. x is all numbers less than four, NOT including four, and it goes on until negative infinity (which is why the line ends in another arrow.)
Similar in the way which the line for the previous example was drawn, to graph what you are trying to graph on a number line, all you need to do is circle -2 the same way, and draw a line along the numberline through -1, 0, 1, 2... and end it in an arrow (meaning if you could, you would go on until infinity)

As for 'how do you find x', well, the answer to that is the question " x > -2 " - that is, " x is all numbers greater than -2 "
Hope this helps :)

Answer 3

to graph inequalities like this, you need to do more than circle the number. You also have to show what part of the number line is, in this case, greater than negative 2. So you go to the right, because those are the numbers that have greater value. Sometimes that's confusing, becase it seems like -3 would be greater that -2. But once you get into negative numbers, it's like going into debt. It is better to owe somebody 2 dollars than 3 dollars. The more you go to the left on the number line, the deeper in debt you go. You want to go to the right and get out of debt.

Answer 4

"x > -2" is simply a linear algebra problem where x= all numbers positive, and greater than -2 (-1.99, -1, -.1, -.09, 0). No circles involved. When the x value = (-) integers, then you go left on the numberline, and the corresponding line for that single integer would be a verticle line parallel to the y-axis.

Answer 5

yes you would circle the number -2 and then draw a line thru the number line going to the right with an arrow at the end of that new line, because that would mean that x is anywhere to the right of that -2. I hope this helps ya...

Answer 6

No, you just circle the negative two and then draw an arrow to the right. The line to the right indicates that you're describing all of the numbers which are greater than negative two, that's what the "x" means.

Answer 7

You would circle, or highlight, or whatever, the entire line to the right of the point where -2 is. x can be anywhere on that part of the line.

Answer 8

x is all numbers greater than -2