2006-09-23 00:33:15 · 7 answers · asked by double B 2 in Science & Mathematics ➔ Mathematics
i think you mistyped something
2006-09-23 02:35:16 · answer #1 · answered by Sherman81 6 · 0⤊ 0⤋
I'm not sure what an & sign means, but I take it to be addition, since multiplication would be in parenthesis : () for ex: 44(5b)
that would change the answer significantly.
the secret is to solve an equation for y in terms of a and/or b
so, using 44 +5b - y =14
-y= -30-5b
y=30 + 5b
then, substitute that equation for y in another equation
2a + 5b = 44 + 5b - (30 + 5b)
using that equation, solve for a
2a = 44 + 5b - (30 + 5b)
2a= 14
a=7
now we can solve for b
2(a) + 5b = 14
2(7) + 5b = 14
b=0
now let's solve for y again
44 +0 - y=14
y=44-14
y=30
let's try it out
2(7) + 0 = 14
14=14 TRUE
44+0-30=14
14=14 TRUE
Sweet. It works :)
Your answer set then is:
a=7
b=0
y=30
my algebra teacher would be so proud!!!
2006-09-23 00:53:35 · answer #2 · answered by Chelle 3 · 0⤊ 0⤋
2a + 5b = 44 & 5b - y = 14
a=7, b=6, y=16
2(7) + 5(6) = 44 & 5(6) - 16 = 14
14+ 30 = 44 & 30 - 16 = 14
2006-09-23 00:39:10 · answer #3 · answered by jj_wolfblade 1 · 0⤊ 0⤋
Solve,
2a + 5b = 44 ... (1)
5b - y =14 ... (2)
(1) - (2),
2a + 5b -5b + y = 44 - 14
2a + y = 30
a = (30 - y)/2 ... (3)
Substitute (3) into (1),
2[(30-y)/2] + 5b = 44
30 - y + 5b = 44
5b = 44 - 30 + y
b = (14 + y)/5
Therefore the solution set is:
a = (30 - y)/2
b = (14 + y)/5
for all values of y.
2006-09-23 01:37:30 · answer #4 · answered by ideaquest 7 · 0⤊ 0⤋
a=7 b=0 y=30
2006-09-23 02:32:24 · answer #5 · answered by Ultimate Chopin Fan 4 · 0⤊ 0⤋
for solving three unknowns you need three equations
i think the second equation should read 5b-a=14
2a+5b==44
-a+5b=14
subtracting
3a=30 so a=10
substituting a=10 in
-a+5b=14
-10+5b=14
5b=24
b=4.8
the solution set is (10,4.8)
2006-09-23 00:52:22 · answer #6 · answered by raj 7 · 0⤊ 0⤋
2a + 5b = 44 -----eq 1
5b - y =14 --------eq 2
Use subtractionn to cancel out 5b:
2a + 5b = 44
- (5b - y =14)
2a + 5b = 44
-5b + y = -14
2a + y = 30
2006-09-23 00:46:14 · answer #7 · answered by Lin 2 · 1⤊ 0⤋