m-n=-16
m+n=24
2m+0n=8
2m=8
m=4
4-n=-16
-4 -4
-n=-20
n=20
m=4
n=20
2006-09-23 01:47:30
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answer #1
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answered by math_teacher_02 2
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you may desire to apply substitution. So watch x+y = 4 x+y = 8 so which you're taking the 1st equation and decide to a variable, i will decide for for x x+y=4, subtract the y x=4-y Now take that equation that we solved and put in 2d equations presented that all of us people be attentive to what x equals. So (4-y)-y=8 I substituted the x indoors the 2d equation with the x we created indoors the 1st equation. Now you merely decide for for y (4-y)-y=8 4-2y = 8 -2y=4 y=-2 Now plug the Y draw back into the two equations and you're arranged to get the x value. x + (-2) = 4 x-2 = 4 x = 6 So X = 6 Y = -2
2016-12-12 13:29:22
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answer #2
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answered by ? 3
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m - n = -16
Therefore, n = 16 + m
Therefore, m + n = 24 becomes 2m + 16 = 24
From that, we solve for m, (24 - 16)/2 = 4
Sub m = 4 back into m - n = -16
-n = -16 - 4
n = 20
2006-09-23 00:27:28
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answer #3
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answered by Anonymous
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m-n= -16
m+n=24
Use addition to cancel out n:
m-n= -16
+ m+n=24
2m = 8
m=4
then substitute m=4 to any of the equation:
m+n=24
4 +n=24
n=20
Thus the solution set is m=4, n=20
2006-09-23 00:50:36
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answer #4
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answered by Lin 2
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m - n = -16
m + n = 24
2m = 8
m = 4
4 - n = -16
-n = -20
n = 20
ANS : m = 4 and n = 20
2006-09-23 02:36:05
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answer #5
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answered by Sherman81 6
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m-n=-16
m+n=24
we sum up the two equations
2*m=8 => m=4
n=20
2006-09-23 00:26:18
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answer #6
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answered by Patricia Lidia 3
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how will you kids ever learn how to do it if you can jump on the internet ,, get the answer and write it down,,, this is my problem w/ todays youth,, sheesh,,, grab a pencil ,read your mathbook and do it yourself,,,
2006-09-23 00:29:03
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answer #7
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answered by John C 5
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m-n+m+n=24-16
2m=8
m=4
4+n=24
n=20
r u solving ur math's problem here?!!!!
2006-09-23 00:37:39
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answer #8
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answered by marjan m 3
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The Aztec rides away.
2006-09-23 00:26:03
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answer #9
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answered by L S 3
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hello,
your answer is the
(a,b)=(4,20)
to find more answer
contact us directly
by email
sumantdguthe@yahoo.co.in
2006-09-23 00:48:41
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answer #10
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answered by suma 1
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