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working please :)

2006-09-23 00:17:02 · 7 answers · asked by itype2fast 1 in Science & Mathematics Mathematics

7 answers

I think it's already simplified but if you want you can factor it:

3(x-sqrt3)

2006-09-23 00:56:55 · answer #1 · answered by Lin 2 · 1 0

a million 20xy^3 .. sqrt of four hundred = 20, sqrt of x^2 = x, sqrt of y^6 = y^(6/2) = y^3 #2 4a^2 b^(2/3) .. dice-rt of sixty 4 = 4, dice-rt of a^6 = a^(6/3) = a^2, and b^2 must be written as both dice-rt (b^2) or b^(2/3) #3. undrt (2 hundred) = undrt (100 x 2) = 10 undrt(2) undrt(2)*10x^(3/2)y^(a million/2) / undrt(2)x^(a million/2)y^(5/2) undrt(2) go out and we carry all powers to the suitable by making use of including a minus signal to the means of the denominator. 10x^(3/2 - a million/2)y^(a million/2 - 5/2) = 10x^3 y^-2 = 10x^3 / y^2 i have achieved the first 3 as examples, they are all ordinary. attempt them your self! a million / x = x^-a million and once you squarert, you divide the means by making use of two. once you dice-rt, you divide the means by making use of three. #9. sqrt (3x+8) = 2 you merely ought to sq. both aspect. meaning you multiply the means of both aspect by making use of two. a squarert is a means of one million/2, a dice root of one million/3, etc. (3x+8)^(a million/2) = 2 squaring both aspect, (3x+8)^(a million/2)*2 = 2^a million*2 3x+8 = 4 3x = -4 x = -4/3 -- for rationalizing, if it truly is of the kind, say: 3/ undrt(3). you multiply it & divide it by making use of the denominator. 3 undrt(3) / undrt (3) * undrt (3) = 3 undrt(3) / 3 = undrt (3) if it truly is of the kind, say: a million/[a million + undrt(2)] , then you extremely multiply and divide it by making use of a million - undrt(2). this brings it to an (a-b)(a+b) style, which equals a^2 - b^2 a million - undrt(2) / (a million + undrt 2) (a million - undrt 2) interior the denominator, a = a million, b = undrt 2 so, [a million - undrt (2)] / a million + [undrt (2)]^2 = [a million - undrt (2)] / a million + 2 [a million - undrt(2)] / 3 9 minutes in the past

2016-11-23 16:54:47 · answer #2 · answered by Anonymous · 0 0

You could factor out the 3

3(x - /3)

2006-09-23 02:55:24 · answer #3 · answered by whatthe 3 · 0 0

3x-3(sqrt)3
=3(x-(sqrt)3)
this is the answer if you will only simplify.

2006-09-23 00:26:50 · answer #4 · answered by Anonymous · 1 0

3x - 3/3 = 0
3x = 3sqrt3
9x^2=27
x^2=3
x=sqrt3
I'm just guessing so don't use my solution unless it's correct.

2006-09-23 00:24:57 · answer #5 · answered by OU812 5 · 0 0

take out rt 3 as common factor
3x-rt3=rt3(rt3x-1)

2006-09-23 00:55:50 · answer #6 · answered by raj 7 · 0 0

3(x-1). sqrt(3).
----------------
3


=(x-1)sqrt(3)

2006-09-23 00:20:36 · answer #7 · answered by iyiogrenci 6 · 0 0

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