Using elimination,solve:6a+10b = 45 & 10b=4a -25. Wats the sol. set?

Answer 1

6a+10b = 45------eq 1
10b=4a -25-------eq2

Subtract eq 2 from eq 1:

6a+10b = 45
- (10b=4a -25)

6a+10b = 45
-10b= - 4a +25

6a = -4a + 70
10a=70
a=7

Substitute a=7 to any of the equations:

6a+10b = 45
42 + 10b = 45
10b = 3
b= 3/10

Ans: a=7, b= 3/10

Answer 2

6a + 10b = 45
10b = 4a - 25


6a + 10b = 45
-4a + 10b = -25

6a + 10b = 45
4a - 10b = 25

10a = 70
a = 7

10b = 4(7) - 25
10b = 28 - 25
10b = 3
b = (3/10)

ANS :
a = 7
b = (3/10)

Answer 3

6a+10b = 45
10b=4a -25

6a+4a-25=45
10a=70 => a=7

10b=28-25
10b=3
b=3/10

Answer 4

It goes like this:

6a+10b=45
4a -10b=25 I transposed them
---------------
10a+0 =70 Find a way to subtract one of the variables and make it zero (I subtracted +10b and -10b by adding them)

10a=70 Divide both sides by 10
----- ----
10 10

a=7




6(7)+10b=45 Substitute one of the equation's letter "a"

42+10b=45

10b=45-42

10b=3

b=0.3

The answers are:

a=7
b=0.3

Its right. Try to check it by substituting them to both equations.
The solution set is (7,0.3) or (7,3/10)
But wait, a solution set is (x,y). But the letters are a and b.
So I'm not quite sure about the answer.

Answer 5

6a+10b= 45 ........ (1)
10b=4a-25 ...........(2)
(2) -4a+10b =-25
(1)- (2) 10a=70
a=7,
(1) 6(7) +10b=45
10b=3,
b=0.3

Answer 6

6a+(4a-25)=45
10a-25=45
10a=45+25
10a=70
a=7
10b=4*7-25
10b=3
b=3/10

Answer 7

6a+10b=45
4a-10b=45

add them
10a =90
a=9
b=-0,9

Answer 8

6a+10b=45

10b=4a-25
-4a+10b=-25
or
4a-10b=25

6a+4a=70
10a=70
a=7

6(7)+10b=45
42+10b=45
10b=45-42
10b=3
b=0.3

Answer 9

solution set of your problem is
(a,b)=(7,0.3).
okkkkkkkkkkkk.