72 pupils from Evergreen School sold a total of 1260 tickets.1/6 of them sold thesame number of tickets each and the rest of the pupils sold 4 times as many tickets as each of the pupils in the first group.How many tickets did each child in the second group sell?
2006-09-22 21:36:55 · 16 answers · asked by tocatchtheuncatchableii 3 in Science & Mathematics ➔ Mathematics
every one in first group sold x tickets
every one in second group sold y tickets
1/6 * 72 = 12
72 - 12 = 60
so
12 x + 60 y = 1260
y = 4x
12 x + 240 x = 1260
252 x = 1260
x = 5
y = 20
*******************
each one in the 1st group sold 5 tickets
each one in the 2nd group sold 20 tickets
2006-09-22 21:50:05 · answer #1 · answered by M. Abuhelwa 5 · 1⤊ 0⤋
Stay in school, kids. Don't do drugs, kids.
That aside =p...
Organise your information so you know with what you're dealing.
72 pupils total.
Group 1 is one-sixth of the total. Group 1 is 72*(1/6) or (72/6).
--Group 1 is therefore made up of 12 pupils.
Group 2 is the rest. (five-sixths, but here, since there are only two groups, it's easier to just subtract from the total). Group 2 is 72 - 12.
--Group 2 is made up of 60 pupils.
Let T be the number of tickets sold by each member of Group 1.
That means that
--Group 1 sold a total of 12T tickets.
The wording of the problem is tricky at this point. Working the problem such that Group 2 sold 4 times as many tickets as Group 1 (or 48T tickets) makes the final answer work out to not-a-whole number.. so the problem must mean that each member of Group 2 sells 4 times as many tickets as each member of Group 1.
Meaning, if the total number of tickets sold is 1260, then Group 2 must have sold a total of 1260 - 12T tickets.
For what we defined as T, each member of Group 2 must sell 4T tickets. That means that
4T = (1260 - 12T)/60
since 60 is the number of pupils in Group 2.
240T = 1260 - 12T
252T = 1260
T = 5
And each pupil in Group 2 sold 4T tickets.
So our final answer is
20 tickets each.
2006-09-23 04:57:22 · answer #2 · answered by winterbourne_nova 2 · 0⤊ 0⤋
It depends a bit on how you read the question. Does 'the rest of the pupils' mean the whole group together or does it mean each individual kid of the 2nd group. I'll explain both. First the individual kid explanation (the most logical outcome)
12 (1/6 of the total) kids sell 1 portion. 60 (the other 5/6of the total) kids sell 4 times more, so 4 portions each.
Total portions 12 x 1 plus 60 x 4= 12 + 240= a total of 252 portions. 1260 tickets sold / 252 portions = 5 tickets per portions
Group 1 per kid 1 portion= 5 tickets per kid
Group 2 per kid 4 portions x 5 tickets= 20 tickets per kid
The 'rest' means 'all of them together':
1/6 is 12 pupils, they each sold 1/4 of what the other group sold
The rest, 60 pupils, can be seen as 4 pupils of group one (the whole group sold 4 times as much as ONE pupil of group 1)
So group one 12 to group two 4, what tells us that group one totals 75% of the total sale and group two 25% :
group one 945 group two : 315 Divided by 60 pupils each kid in group two would have sold an average of 5.25 tickets (group one per kid 78.75. Can't help you with the question how they managed to sell 3/4 and 1/4 tickets)
Math questions should be asked in a way that you can only see them one way. In this case there should have been an extra 'each' between 'pupils' and 'sold 4 times'
2006-09-23 05:11:53 · answer #3 · answered by Patrick L 3 · 0⤊ 0⤋
The 1/6th of the 72 members is 12
so if 12 members sold 5 tickets each then they would have sold 60 tickets
so the number of tickets is reduced to 1200 (1260-60)
so the rest 60 members have sold 1200 tickets
since each of the 60 members have sold 4 times that of the above they have sold 20 tickets each
so if we calculate it back it would be
60*20=1200
12*5=60
total 1260
hope this is what you are looking for :)
2006-09-23 04:52:15 · answer #4 · answered by Sridhar C R 1 · 0⤊ 0⤋
the answer is 20 tickets.because the first group pupils ls (1/6*(72))=12.so lf you take single pupil sold 5 tickets.total of the first group sold is 60 tickets.u said that second group pupil sold is 4 times greater than first so u take the second one ticket sold is 20.(60 pupils*20=1200).so total 1200+60=1260. solved
2006-09-23 05:02:22 · answer #5 · answered by Ramadoss G 1 · 0⤊ 0⤋
1/6 times 72 pupils times (number of tickets) plus 5/6 times 72 pupils times 4 times (number of tickets) = 1260
Multiply the answer to that by 4 for the answer.
OR...1/6 times 72 pupils times( number of tickets) plus 1/12 times 4 times ( number of tickets) = 1260
depends on how you read the question. This seems more of an interpretation problem than an algebra problem.....hopefully you will never come across a problem like this in real life!!! The difference between 'each and evey one' and 'each single one' is significant. You can rattle off ...each of those ....and 'mean' ...all of those
2006-09-23 04:57:09 · answer #6 · answered by eantaelor 4 · 0⤊ 0⤋
ok. 1/6 of 72 is 12 so group 1 is 12 people and group 2 is 60 people. so group 1 sould 5 tickets each and group 2 sold 20 each. 12*5+60*20=1260
2006-09-23 04:51:21 · answer #7 · answered by stormie a 2 · 0⤊ 0⤋
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1/6 of the 72 students sold x tickets:
1/6*72*x=12x
The rest of the students sold 4 times as many tickets as the first 12, so:
4*12x=48x
The total number of tickets sold is 1260, so:
12x+48x=1260
60x=1260
c=1260/60=21
48*21=1008 tickets sold by the second group.
2006-09-23 04:48:25 · answer #8 · answered by druid 7 · 0⤊ 0⤋
20 in total
2006-09-23 06:45:39 · answer #9 · answered by xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx 2 · 0⤊ 0⤋
72/6=12
72-12=60
12x+60(4x)=1260
12x+240x=1260
252x=1260
x=1260/252=5
4x=?
4*5=20
Answer 20
2006-09-23 04:46:35 · answer #10 · answered by iyiogrenci 6 · 0⤊ 0⤋