Find a ten digit number such that :?

Question

the first two digits are divisible by 2,the first 3 digits by 3,the first 4 digits by 4 and so on till 10.i.e.,the last digit will obviously be zero. Also, all the 10 digits are unique and non repeating

Answer 1

3816547290.

Answer 2

The Answer is 3816547290

First 1 Digit ::3divided by1equal to3
First 2 Digits ::38divided by2equal to19
First 3 Digits ::381divided by3equal to127
First 4 Digits ::3816divided by4equal to954
First 5 Digits ::38165divided by5equal to7633
First 6 Digits ::381654divided by6equal to63609
First 7 Digits ::3816547divided by7equal to545221
First 8 Digits ::38165472divided by8equal to4770684
First 9 Digits ::381654729divided by9equal to42406081
10 DIGITS ::3816547290divided by10equal to381654729

Answer 3

The last digit has to be zero so we keep it out.
5th digit has to be 5
9th digit can be anything because any prrmutation of 1-9 is divisible bt 9.
the 2nd 4th 6th and 8th digit have to be even
let us have 3digit number divisible by 8 1st is even no 5 no 0
The middle digit has to be odd as 2nd 4th 6th 8th 10th even so all rest odd
216,296,416,432,472,496,632
we can proceed like this

Answer 4

22 333 4444 55555 666666 7777777 88888888 999999999 1010101010

Answer 5

This question is answered already by some Seniors and do see above

Answer 6

22, 333, 4444, .... etc...