2.4x^2 - 9.12x + 0 = 0
x= ( -b +- V(b^2 - 4ac) ) / 2a
a=2.4
b= -9.12
c=0
x = (9.12 +- 9.12) / 4.8
x = 0 or 3.8
It's actually easier to solve this WITHOUT the formula.
2006-09-22 17:33:42
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answer #1
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answered by i_sivan 2
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I'm assuming you meant
2.4x^2 - 12.72x + 3.6 = 0
240x^2 - 1272x + 360 = 0
24(10x^2 - 53x + 15) = 0
10x^2 - 53x + 15 = 0
x = (-b ± sqrt(b^2 - 4ac))/(2a)
x = (-(-53) ± sqrt((-53)^2 - 4(10)(15)))/(2(10))
x = (53 ± sqrt(2809 - 600))/20
x = (53 ± sqrt(2209))/20
x = (53 ± 47)/20
x = (100/20) or (6/20)
x = 5 or (3/10)
ANS : x = 5 or (3/10)
2006-09-23 01:25:59
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answer #2
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answered by Sherman81 6
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Did you print that out correctly because that's not a quadratic equation. Should their really be an x after the 3.6 or was that a mistake?
2006-09-23 00:34:53
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answer #3
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answered by angeliquedesjardins 3
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If you've written the equation correctly, the equation simplifies to:
2.4x^2-9.12x+0=0
a=2.4, b=-9.12, c=0
x = 0 and -3.8
2006-09-23 00:34:53
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answer #4
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answered by Steven Jay 4
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How nice that folks aren't just doing your homework for you.
Well...
ax^2 +bx +c = 0...
a = 2.4, b= (-12.72 +3.6), c = 0.
What's the problem?
2006-09-23 00:34:53
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answer #5
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answered by Art_333 2
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I think it's 2.4x^2 - 12.72x + 3.6 = 0
divinding by 2.4 we get
x^2 - 5.3x + 1.5 = 0
add (5.3/2)^2 to both sides or 2.65^2
x*2 -5.3x + 1.5 + 2.65^2 = 2.65^2
(x-2.65)^2 = 5.5225
x-2.65 = + or - sqrt(5.5225) = + or - 2.35
x= 2.35 + 2.65 = 5 or x= -2.35 + 2.65 = 0.3
2006-09-23 00:39:23
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answer #6
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answered by Anonymous
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Same answer as that of Rajesh Kochhar. He is right!
2006-09-23 00:29:52
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answer #7
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answered by quidwai 4
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first times all the integers by 10.....u will find out dis is easier....the answer is(x-5)(3x-10)......x=5or0.3
2006-09-23 05:42:07
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answer #8
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answered by Anonymous
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Why cannot you do it yourself?Tell us where you got stuck.
2006-09-23 00:26:47
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answer #9
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answered by Rajesh Kochhar 6
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I did my homework. Why do I need to do your too??
2006-09-23 00:36:24
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answer #10
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answered by ky_school_teacher 2
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