The formula for the slope of the straight line going through the points (x1, y1) and (x 2, y 2) is given by:
m= y2 - y1 / x2 - x1
2006-09-22 16:23:04
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answer #1
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answered by Huda H 2
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y - y1 = m(x - x1)
It is a formula you use when you know a point on the line, and you know, or have figured out, the slope. M is the slope. Y1 and x1 are the coordinates of the point. So if you have a point at
(2, -5) and a slope of 1/2 the formula would look like this.
y - (-5) = 1/2(x - 2)
Then solve it.
2006-09-22 15:39:38
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answer #2
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answered by huckleberry 5
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It stems from the formula for a straight line y = mx + c
If x1,y1 and x2, y2 are two points on the line then the solpe m can be determined by the formula:
m = (y2-y1)/(x2 - x1)
Take a look at:
http://www.themathpage.com/alg/slope-of-a-line-2.htm
http://www.algebrahelp.com/messageboards/messages/2948.html
2006-09-22 16:53:59
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answer #3
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answered by Rustom T 3
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dont worry
equation is (y-y1)=m(x-x1)
don't worry about y and x, u need only find y1,m,x1
m=slope(they will give u or find it by using(y2-y1)/(x2-x1)
they will give you some thing like this(2,3) or (1,-2) etc
then Y1=3 in (2,3)
X1=2(2,3)
then find out the answer. u can write 2 type of answer
1. slope-intercept Y=Mx+B
2. general formula A+B=C
2006-09-22 17:59:10
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answer #4
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answered by ♣♣♣oh yeah♣♣♣ 2
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y-y1=slope(x-x1) i think most use m 4 slop
some ppl may use diff letters so ill break it down
say u have points (3,5) and (4,6) 3=Y 5=x 4=y1 6=x1
2006-09-22 15:35:05
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answer #5
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answered by Anonymous
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y-y1 =m(x-x1)
y1=y subscript 1
x1=x subscript 1
2006-09-22 15:40:21
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answer #6
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answered by chococat 4
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y - k = m(x - h)
The line goes through point (h,k) and has slope m.
2006-09-22 15:34:17
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answer #7
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answered by DavidK93 7
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(y - y1) = m(x-x1)
(y1,x1) is your point
m is your slope
and you know what x and y are
2006-09-22 15:35:30
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answer #8
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answered by sur2124 4
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(y-y1)=m(x-x1) then plug n chug from there
2006-09-22 15:39:39
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answer #9
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answered by ftballplyr 1
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y - y1 = m ( x - x1 )
2006-09-22 15:39:17
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answer #10
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answered by Anonymous
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