2^x=x^2
how do you solve this mathmaticaly?
2006-09-22 14:35:25 · 5 answers · asked by aznskillz 2 in Science & Mathematics ➔ Mathematics
x=-.7666 or 4 or 2 use ln
2006-09-22 14:52:58 · answer #1 · answered by RichUnclePennybags 4 · 0⤊ 0⤋
x=2 works and x=4 does as well.
2006-09-22 21:47:23 · answer #2 · answered by True Blue 6 · 0⤊ 0⤋
Try graphing the functions y = 2^x and y = x^2 on a graphing calculator, then solve for the points of intersection.
2006-09-22 21:39:09 · answer #3 · answered by whatthe 3 · 0⤊ 0⤋
you can solve it numerically. Give x an intial value and iterate, continuing guessing until both sides of the equation are equal, then you get a value for x.
2006-09-22 21:38:07 · answer #4 · answered by Sporadic 4 · 0⤊ 0⤋
Heh, just eyeballing it, you can tell that x=2 works. :-)
2006-09-22 21:37:06 · answer #5 · answered by Bramblyspam 7 · 0⤊ 0⤋