The length of a rectangle is 1cm more than 4 times its width. Area equals 66cm^2, find dimensions.?

Question

find the answer to the nearest thousandths.

Answer 1

I always recommend that people draw a rectangle and label the sides. Two sides will each be w to represent the width. The other two sides will each be 1 + 4w to represent 1 more than 4 times the width.

Area is length times width, so w(1 + 4w) = 66
4w^2 + w = 66
4w^2 + w - 66 = 0
Use quadratic formula to solve for w. Make sure that none of your answers will result in a negative length or width.

Answer 2

ok, so the size would be L and the width would be W right here is what all of us understand: (a million) L = 4W section is length circumstances width, so (2) LW = 64x² if we replace (a million) into (2) we get 4W² = 64x² now divide the two factors by potential of four W² = 16x² take the sq. root of the two factors W = 4x putting this lower back into (a million) L = 4(4x) = 16x and perimeter = 2W + 2L = 2(4x) + 2(16x) = 8x + 32x = 40x so the rectangle is 4x by potential of 16x with a edge of 40x

Answer 3

L = 4W + 1
L*W = 66

Solve using simultaneous equations:

L*W = (4W + 1)*W = 4W^2 + W
4W^2 + W = 66
4W^2 + W - 66 = 0

Solve for W using the quadratic equation
W = -b +/- sqrt(b^2 - 4ac) / 2a
Then get L.

Answer 4

l=4w+1
lw=66

l = 4(66/l) + 1
l*l = 4*66 + l
l^2 -l - 4*66 = 0
the rest is an exercise for the student

Q.E.D.

Answer 5

look in your book for examples and solve that way. that is the only way you will learn instead of people doing the work for you :)

Answer 6

i suggest you figure it out for yourself rather than asking the world to do it for you. kids today..............