a.t>1/6
b.t<-1/3
c.t<-30
d.t<-16
e.t>15/2
f.t<27/5
2006-09-22 13:20:07 · 4 answers · asked by cherryvalley2006 2 in Science & Mathematics ➔ Mathematics
d
2t+5<-27
2t<-32
t<-16
2006-09-22 13:30:58 · answer #1 · answered by anonymous_20003 3 · 0⤊ 0⤋
Operate as you were solving an equation.
(2t + 5)/3 < -9
First, multiply both sides by 3
2t + 5 < -27
Subtract 5 from both sides
2t < -32
Divide both sides by 2
t < 16
Note: When solving inequalities the operator (< or >) changes direction if you multiply or divide both sides by a negative number.
3 > -4
If you multiply by -1
-3 < 4 is the result.
2006-09-22 20:41:41 · answer #2 · answered by kindricko 7 · 0⤊ 0⤋
d. t< -16
2t+5/3 < -9
2t + 5 < -27
2t < -32
t < -16
2006-09-23 01:26:53 · answer #3 · answered by Yaritza 3 · 0⤊ 0⤋
(2t + 5)/3 < -9
2t + 5 < -27
2t < -32
t < -16
ANS : d.)
2006-09-23 01:57:35 · answer #4 · answered by Sherman81 6 · 0⤊ 0⤋