1. The probability of getting a 5 then a 2 is 1/8 *1/7 = 1/56
The probability of getting 2 then a 5 is 1/8*1/7 = 1/56
The probability of ending up with 2 and 5 (any order) is 1/56 + 1/56 = 2 /56 = 1/28
2. Assuming you want the probability of two odd numbers:
The probability of drawing the first odd number is 4/8
Now the probability of drawing another odd number is 3/7
The probability of the two events occuring is:
4/8 x 3/7 = 12/56 = 3/14
2006-09-22 12:33:06
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answer #1
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answered by Tammi J 3
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the cards that are present are 1,2,3,4,5,6,7,8.
the probability of getting a 2 and a 5:
the probability of getting a 2 as the first card is 1/8, since there is only one 2 card out of a possible 8.
the probability of getting a 5 next is 1/7, since there is only one 5 card out of a possible 7 (as the first card is not replaced).
therefore the probability of this happening is
1/8 x 1/7 = 1/56
but we have to take into account that there are 2 ways of getting the 2 and 5 card; getting the 2 first than the 5, or getting the 5 first then the 2.
so the actual probability is 2(1/56) = 1/28.
probability of getting 2 odd numbers:
first of all, ask yourself how many odd numbers are there from 1-8?
there are 4 odd numbers from 1-8 (1,3,5,7).
the probability of drawing an odd numbered card the first time is 4/8, since there are 4 possible outcomes out of the total 8.
the probability of drawing a second odd card is the first card is not replaced is now 3/7, since there are now 3 odd cards left out of a possible 7.
therefore, the probability is 4/8 x 3/7 = 3/14.
hope this helped! good luck with stats!
2006-09-22 12:40:02
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answer #2
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answered by Anonymous
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The odd numbered cards are:1,3,5,7
The even numbered are:2,4,6,8
Assuming that the first card was not a 5, the probability of the second card being a 5 is: 7 out of 8.
Same odds for the 2.
Probability of 2 odd numbers being drawn are:3 out of 8, for the first card drawn, and 2 out of 8 for the second.
2006-09-22 12:52:57
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answer #3
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answered by hollyltstarfleet 4
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To find the probability of two odd numbers, first find the total number of two card combinations. This is (8x7)/2=28. There were 8 cards on the first draw times 7 cards on the second draw, and you divide by two because there are two ways each combination can come and the order does not matter. The number of odd/odd combinations is(4x3)/2 or 6.( I got this by multiplying 4 odd cards on the first draw times three odd cards on the second draw and then dividing by 2 because each combination could come in two different orders and we don't want to count each combination twice. It doesn't matter if we draw 1 then 3 or 3 then 1. It's still just one combination.)). So the probability that both are odd is 6/28 or 21.44 %. To find the probability of the two cards being 5 and 2,first calculate how many 2 card combinations are 5-2. In your 8 card deck there is only one such combination so the probability is 1/28 or 3.57%.
2006-09-22 12:50:10
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answer #4
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answered by True Blue 6
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There are a couple of ways to do this problem. One way is to list ALL the ways that you could draw 1 card and then another. Count the ones that satisfy your condition. Divide by all the ways that you could do it.
However, it is easier to do it this way:
Find the probability that the first card drawn is odd. Then, assuming the first card was odd, what is the probability that the 2nd one is odd.
P(first card odd) = 4/8
P(2nd card odd) = 3/7
P(both odd) = 4/8 * 3/7 = 3/14
2006-09-22 12:34:11
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answer #5
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answered by tbolling2 4
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3/14
2006-09-22 12:38:15
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answer #6
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answered by ana3 2
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3/14
2006-09-22 12:32:21
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answer #7
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answered by anonymous_20003 3
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2016-12-18 15:10:17
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answer #8
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answered by ? 4
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