Can some one put this function in simple form :t^3+3t^2-12t+4=0?

Question

FACTORED FORM

Answer 1

Look at the values, what can you factor out of them? you can group the numbers with t and factor out t.

t(t^2+3t-12)+4=0

or you can group the t^3+3t^2 and -12t+4 to get:
t^2(t+3)-4(3t-1)=0

you can group them different ways to get different answers, I dont know what chapter you are on or what your teacher is looking for.

Answer 2

you can do that.
if you sat t=2 and apply to the equation, it will be equal to zero, therefore (t-2) is a factor of that function, by using a factor theorem,

so now if you devide function by (t-2) you get (t^2 +5t-2)
so: t^3+3t^2-12t+4=(t-2)(t^2+5t-2);
you cant make (t^2+5t-2) in two brakets, so you have to use quadratic equation to solve what is the other solutions for t;
and the formula of the quadratic is:
t=(-b+/-√b^2-4ac)/2a
where a,b,c are the Coefficient of t in the quadratic equation (t^2+5t-2) which is
a=1 b=5 and c=-2

hope you understand it, if not i will try to expain more

Answer 3

that is simple form.

Or do you mean factored?