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If f(t) is the quantity in grams of a chemical produced after t minutes and g(t) is the same quantity in kilograms, then f'(t) = 1000g'(t).

Please explain to me wheter this statement is true or not.

2006-09-22 10:30:37 · 3 answers · asked by Anonymous in Science & Mathematics Mathematics

f ' (t) means the derivative of the function f and
g ' (t) means the derivative on function g

2006-09-22 10:39:22 · update #1

3 answers

First, we can agree that f(t) = 1000g(t), right?

If I produce 1000 grams after one second, that is the same as 1 kg. So in this example f(1) = 1000 and g(1) = 1. f(1) = 1000 * g(1). In general f(t) = 1000g(t).

But you asked about the derivatives of the two functions.
Let's imagine the functions were:
g(t) = t^3 + t^2 + 8
f(t) = 1000 (t^3 + t^2 + 8)

This satisfies the first statement.

Now take the derivative of both:
g'(t) = 3t^2 + 2t
f'(t) = 3000t^2 + 2000t = 1000 ( 3t^2 + 2t )

So f'(t) = 1000*g'(t).

Stated more simply, the derivative is the slope or the "rate" of change in the function. For every point, the rate of change of f(t) will be 1000 times the rate of change of g(t), because the measurement in grams is 1000 times the measurement in kilograms.

2006-09-22 10:34:22 · answer #1 · answered by Puzzling 7 · 1 1

it's true, the rate of producing grams will be 1000 times greater than the rate of producing kilograms

2006-09-22 10:43:43 · answer #2 · answered by Greg G 5 · 0 0

False. If f(t) is grams and g(t) is killograms, then 1000*f(t) = g(t).

2006-09-22 10:34:28 · answer #3 · answered by kooshman38 3 · 1 1

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