a) less than 5%
b) about 10%
c) about 50%
d) greater than 95%
2006-09-22 10:00:29 · 12 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
I must say I am pleasantly surprised by how many actually numerate people are out there in Yahoo!Answersland! (You know who you are). I wish I could give ten points to all the correct answers, but I guess I'll have to go with who got it first...
2006-09-22 10:23:17 · update #1
I must say I am pleasantly surprised by how many actually numerate people are out there in Yahoo!Answersland! (You know who you are). I wish I could give ten points to all the correct answers, but I guess I'll have to go with who got it first...
2006-09-22 10:23:21 · update #2
d
2006-09-22 10:07:22 · answer #1 · answered by Pseudo Obscure 6 · 1⤊ 0⤋
Dear Thin Kaboudit,
In your question, you have asked what are the chances that 2 of the 56 share the same birthday. You did not say birth date. There are 7 different days that a person could be born on. The total of people does not matter because all of them had to be born on 1 of the 7 days of the week. Therefore, there is a 1 in 7 chance that both individuals were born on the same day. My answer is about 10%.
2006-09-22 10:20:55 · answer #2 · answered by pilgrim_153 3 · 0⤊ 1⤋
The more people present, the greater the chance for this to happen.
56 / 365 x 100% = 15â342........%
The is (b), about 10%.
2006-09-22 10:49:40 · answer #3 · answered by Brenmore 5 · 0⤊ 0⤋
With 50 people you have a 3% chance
That you will not have the same Birthday.
So the closest answer is
56 with a 95% chance
The answer is D
.
2006-09-22 10:46:22 · answer #4 · answered by Scooby 3 · 0⤊ 0⤋
D Greater then 95%
2006-09-22 10:12:11 · answer #5 · answered by Master J 4 · 0⤊ 0⤋
I say a). Because I calculated it to be (56!/(54!2!)) * (1/365)^2 * (364/365)^54 which I calculated to be approximately .9968% which is considerable less then 5%.
(Note: That is if you don't mean the same year, just the same date.)
2006-09-22 10:20:53 · answer #6 · answered by yljacktt 5 · 0⤊ 0⤋
There are 365 days a year.
56 people
So, the chances are 56/365
204,4%
d) greater that 95%
2006-09-22 10:08:50 · answer #7 · answered by Max Camer 1 · 0⤊ 0⤋
d) greater than 95%.
The odds are just better than even when you have 27 people present.
2006-09-22 10:09:06 · answer #8 · answered by Ralfcoder 7 · 0⤊ 0⤋
= 1 - P(none have the same birthday)
P(none have the same birthday)
= (365*364*363* ... *311*310) / (365^56)
= (365!)/(309!) / (365^56)
= .0117 (according to Matlab)
so that P(2 have the same birthday)= .9883
2006-09-22 10:36:33 · answer #9 · answered by vinzklorthos 2 · 0⤊ 0⤋
a) less than 5%
2006-09-22 10:03:01 · answer #10 · answered by darkrobman 1 · 0⤊ 0⤋
(a)less than 5%
2006-09-22 10:05:12 · answer #11 · answered by raj 7 · 0⤊ 0⤋