$20000 in two accounts, one took a loss of 4%, 12% profit on other, ending up breaking even. How much was invested in each account. Please dont tell me the answer, just how to write it, thank you
2006-09-22 09:57:39 · 5 answers · asked by leroy 1 in Education & Reference ➔ Homework Help
have x = the amount in the first accout with a loss of 4%
have 20000-x = the amount in the second account with a gain of 12%
This would represent the loss in the first account:
(x-.04x)
This would represent the gain in the second account:
[(20000-x)+.12(20000-x)]
So if they broke even, both of these added together would equal 20000:
(x-.04x)+[(20000-x)+
.12(20000-x)]=20000
then just solve for x to find the amount in the 4% account
then plug that number into 20000-x to find the amount in the 12% account.
2006-09-22 10:05:03 · answer #1 · answered by Anonymous · 0⤊ 0⤋
a + b = 20000
a-.04a = b + .12b
There are other ways you could write it though. If you want just one variable:
x - .04x + (20000 -x) + .12 (20000-x) = 20000
2006-09-22 17:01:21 · answer #2 · answered by Goddess of Grammar 7 · 0⤊ 0⤋
iloveleilaandolivia's answer is very helpful and correct!
2006-09-22 18:48:01 · answer #3 · answered by Isaac 2 · 0⤊ 0⤋
since it broke even, I think .04a = .12b
2006-09-22 17:08:01 · answer #4 · answered by Greg G 5 · 0⤊ 1⤋
Duh using language and figures like wot you learn at school.
Wot a numbus
2006-09-22 16:58:50 · answer #5 · answered by Anonymous · 0⤊ 1⤋