A rock thrown straight up climbs for 1.99 s, then falls to the ground. Neglecting air resistance, with what velocity did the rock strike the ground? Answer is in m/s.
2006-09-22 09:26:07 · 5 answers · asked by P 1 in Science & Mathematics ➔ Mathematics
you cannot answer without the initial velocity Vo that is the speed when first thrown up, because you use that to see how high it went in 1.99 seconds. then from that height use the acceleration of gravity -9.8m/s^2 to deterimine final velocity aka (speed at impact)
FYI gravity has NO speed only an acceleration.
Equation is more like: final velocity= height (-9.8m/s^2)
2006-09-22 09:35:53 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Velocity = 10 meters per second, squared...at least when I was in school so many years ago....
V = (10 x 1.99) squared. or 396.01 meters per second, when it hit the ground.
I wonder how long the rock was motionless after stopping in mid air...
2006-09-22 16:34:31 · answer #2 · answered by cbmaclean 4 · 0⤊ 0⤋
can't know, unless we know the velocity of the rock, going up.
2006-09-22 17:24:23 · answer #3 · answered by Vince M 7 · 0⤊ 0⤋
Around 20m/s
2006-09-22 16:34:03 · answer #4 · answered by Anonymous · 0⤊ 0⤋
do ur hw by urself!
2006-09-22 16:33:10 · answer #5 · answered by Anonymous · 0⤊ 1⤋