0.03*6662=?
2006-09-22 08:29:06
·
answer #1
·
answered by Anonymous
·
0⤊
0⤋
You would have to multiply the 6,662 by 3%-you need to change 3% to decimal form in order to multiply it. With a percentage-the decimal is always considered to be at the end, and then you move the decimal two places to the left. So, 3% would be .03 and mulitply that by 6,662 and you would get this 6,662 x .03 = 199.86 This answers your ? of what is 3% of 6,662
Now if someone took away that 3%, which is 199.86 then you would have 97% left. So, take the 6,662 minus the 199.86 and you would get
6,462.14 but the easiest way is to take 6,662 and multiply it by 97%
6,662 x .97 =6,462.14
This answers your second part -how much is left after someone gets that 3%
2006-09-22 08:39:54
·
answer #2
·
answered by Hestia 4
·
1⤊
0⤋
If you have 6,662(100%) left and someone get 3% of it then you have left with 97%.
so,97%of 6662=97*6662/100=6462.14
so, 3%out of 6662=6662-6462.14=199.86
2006-09-22 08:48:31
·
answer #3
·
answered by Anonymous
·
1⤊
0⤋
your english isn't very good.
If you have 6,662 and someone takes 3% then you have 97% left, which would be 6662*0.97 =
and then if you want 3% then it would be 6662*0.03
2006-09-22 08:29:23
·
answer #4
·
answered by ///M5 1
·
0⤊
1⤋
your answer is: multiply 6662 by 3% = 199.86
now subtract the 3% to find out how much would be left
6662-199.86 =6462.14
2006-09-22 21:08:36
·
answer #5
·
answered by soar_2307 7
·
0⤊
0⤋
multiply .03*6662
=199.86
now subtract the 3% to find out how much would be left
6662-199.86
=6462.14
remember %s are decimals:
3% is .03
25% is .25
155% is 1.55
etc.
2006-09-22 08:31:11
·
answer #6
·
answered by Anonymous
·
0⤊
0⤋
3/100*6662/1=19,986/100=199.86
2006-09-22 12:30:39
·
answer #7
·
answered by bestfriendsforever248953 2
·
0⤊
0⤋
just do 6662*.97=6462.14 easiest way
2006-09-22 21:10:39
·
answer #8
·
answered by RichUnclePennybags 4
·
0⤊
0⤋
Is 97% is 6462.14
2006-09-22 08:29:55
·
answer #9
·
answered by runlolarun 4
·
0⤊
0⤋
You need to pay attention during class.
2006-09-22 08:37:36
·
answer #10
·
answered by faversham 5
·
1⤊
0⤋