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Find the derivative of:

f(x)= square root of 6+53+pi

Can you also explain how to do the problem.

2006-09-22 05:46:29 · 3 answers · asked by Anonymous in Education & Reference Homework Help

3 answers

This is actually very easy.

The derivative of a constant is always 0. If there is no variable, then the derivative is 0.

f'(x) therefore is 0 + 0 + 0 = 0.

2006-09-22 05:52:11 · answer #1 · answered by ³√carthagebrujah 6 · 0 0

f(x)=(6)^1/2+53+pi
f'(x)=0 as the derivative of a constant is zero

2006-09-22 12:51:29 · answer #2 · answered by raj 7 · 0 0

the derivative is zero

because no x variable in the function.

the derivative of a constant number is zero.

2006-09-22 12:57:35 · answer #3 · answered by iyiogrenci 6 · 0 0

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