Please also explain how you solved this answer. Thanks!!
2006-09-22 03:48:59 · 10 answers · asked by dotmilind 1 in Science & Mathematics ➔ Mathematics
Both a) and c): the third side is longer than the other two added together.
2006-09-22 03:52:19 · answer #1 · answered by Dave_Stark 7 · 2⤊ 1⤋
All triangles have the side inequality property whereby the sum of any two sides has to be greater than the third side. So add up 2 sides and check if the sum is greater than the third side or not.
a) 5+5 =10 which is less than 11 ,so not possible.
b) 6+4= 10 which is greater than 9, next
6+9= 15 which is greater than 4, next
4+9= 13 which is greater than 6 so since all three are true ,
this triangle is possible.
c) 4+3 = 7 which is less than 8, so not possible.
d) 5+5 = 10 which is more than 5 and since this is true for all the other options , so true.
2006-09-22 04:24:59 · answer #2 · answered by jazideol 3 · 1⤊ 1⤋
In a triangle, any two sides added together must be greater than the length of the third side, otherwise it won't be a triangle. So a) is not a triangle because 5+5=10<11 and c) is not a triangle becuase 4+3=7<8.
2006-09-22 03:59:40 · answer #3 · answered by banjuja58 4 · 1⤊ 1⤋
The Triangle Inequality says,
"The sum of the lengths of any two sides of a triangle must be greater than the length of the third side."
That is, for any Triangle with sides a,b and c, we should have
a+b > c AND a+c > b AND b+c > a.
Since 5+5 < 11 , Triangle (a) is not possible.
Likewise, 4+3 < 8, Triangle (c) is also not possible.
2006-09-25 19:39:51 · answer #4 · answered by Hanz 2 · 1⤊ 0⤋
a) and c) impossible.
remember that in a triangle the sum the length of two sides must be greater than the third side
for a) 5+5>11 false.
for c) 4+3>8 false
2006-09-22 03:54:40 · answer #5 · answered by iyiogrenci 6 · 3⤊ 1⤋
There is a formula called Heron's Formula for the area of a triangle. Let s = (a+b+c)/2. The area is sqrt(sqrt(s(s-a)(s-b)(s-c))).
If the area is to be real, all the inner bracketed terms must be positive. Triangle (a) has s = 10.5, and (s-11) is negative. Triangle (b) has s = 9.5, all okay. Triangle (c) has s = 7.5, and (s-8) is negative. Triangle (d) has s = 7.5, all okay.
This is the same as everybody else's answer, of course, but the method is slightly different.
2006-09-22 04:41:22 · answer #6 · answered by Anonymous · 1⤊ 1⤋
i think two of those sets are impossible...............those are set a) and set c)..................because sum of two sides of a triangle must be greater than third side
But in case a) 5+5=10 which is not greater than 11 so it is impossible to form a triangle and
in case c) 4+3=7 which is not greater than 8
2006-09-22 03:57:40 · answer #7 · answered by Gaurab N 3 · 1⤊ 1⤋
that's certainly as all aspects of a dice are equivalent length. to come across a aspect once you've the quantity you want to take the dice root of the quantity. so that you want to take the dice root of 800.
2016-11-23 15:06:44 · answer #8 · answered by ? 3 · 0⤊ 0⤋
My guess is C. I don't have a good explaination on how I got this answer. I just tried to picture the angles in my head and answer C seems most unlikley
2006-09-22 03:52:11 · answer #9 · answered by Kelli550 3 · 0⤊ 2⤋
a) and c) cannot be triangles
no 2 sides added together can be less than the third side
2006-09-22 03:55:21 · answer #10 · answered by upf_geelong 3 · 1⤊ 1⤋