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A plane moves from 9°N 60°E to 9°N 60°W. If the plane starts at 2 AM and takes 10 hours to reach the destination, find the local arrival time.

a) 4.30 AM b) 6.00 AM c) 4.00 AM d) 10.00AM

Select the right answer. Please also explain how you have solved this. Thanks a lot!

2006-09-22 03:38:21 · 4 answers · asked by dotmilind 1 in Science & Mathematics Mathematics

4 answers

The plane is traveling a symmetrical distance, regarding the Greenwich Meridian. At the time of departure, at the Greenwich Meridian would be 11 PM (because 60° means 3 time zones, to the west means -3 hours), that means that after 5 hours, when the plane reaches it, it would be 4 AM.
The plane is traveling west for another 5 hours. When it passes Greenwich Meridian, at the destination airport it's 1 AM (again 60°, that is 3 time zones and you deduct 3 hours because it's traveling west), so after 5 hours have passed and the plane had reached destination, it would be 6 AM, that is answer b).

2006-09-22 04:07:48 · answer #1 · answered by Alex 2 · 0 0

That's easy. 5:00 am. Get me my slippers.

I solved it by adding 10 hours to 2 am, then subtract the time difference between 60 degrees East and 60 degrees west, which is precisely 300 minutes. Then went to Arby's and had a cheeseburger and counted the pickles, which was 5.

2006-09-22 03:54:12 · answer #2 · answered by Big Momma Carnivore 5 · 0 0

The correct answer is (c)

The reason why that is correct is because if you look at the possible answers, there are two with 4:xx. It can not be 4:30, because only complete hours are used in the formulation.

2006-09-22 03:51:02 · answer #3 · answered by Anonymous · 0 0

If it is 2 am at 9N 60E, then it is 2 pm at 9N 60W the day before.

after 10 hours, it is midnight at 9N 60W .

so my answer is: e) none of the above

2006-09-22 04:01:29 · answer #4 · answered by upf_geelong 3 · 0 0

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