basic alegebra equations
2006-09-22 02:28:28 · 24 answers · asked by vencedersonflow 1 in Education & Reference ➔ Standards & Testing
-13
multiplying a negative and a positive always equals negative. Then you just subtract 3 from the -10 and get -13
2006-09-22 02:29:30 · answer #1 · answered by golgofrinchian 2 · 0⤊ 0⤋
13
2006-09-22 02:29:50 · answer #2 · answered by Anonymous · 0⤊ 0⤋
2 - 6a = 5 - 3a upload 6a to the two aspects 2 = 5 + 3a subtract 5 from the two aspects -3 = 3a divide the two aspects by using 3 a = -a million Now use this value for a in 4a^2 - 2a + a million remember that a unfavourable circumstances a unfavourable equals a favorable... this comes into play in the two the squaring of a and the -2a... 4(-a million)^2 - 2(-a million) + a million 4*a million + 2 + a million = 4 + 2 + a million = 7
2016-12-12 12:55:22 · answer #3 · answered by Anonymous · 0⤊ 0⤋
7
2006-09-22 09:36:15 · answer #4 · answered by mr_fury666 3 · 0⤊ 0⤋
the answer is -13..
u can calculate this by substituting the value of a in the algebraic eqaution....
this goes like this :
>>2a-3
= 2(-5) - 3
= -10-3
= -13 ans...
2006-09-22 02:38:26 · answer #5 · answered by k_rapture 3 · 0⤊ 0⤋
2(-5)-3=-10-13=-13
2006-09-22 02:31:07 · answer #6 · answered by ariakblue 2 · 0⤊ 0⤋
21
2006-09-22 02:33:28 · answer #7 · answered by collie_555 2 · 0⤊ 0⤋
-13
(2 x -5) + (-3)
(-10) + (-3) = -13
2006-09-22 02:30:23 · answer #8 · answered by Jazz 4 · 0⤊ 0⤋
2(-5)-3=-13
2006-09-22 17:15:06 · answer #9 · answered by SABHA A 2 · 0⤊ 0⤋
-13
2006-09-22 02:29:32 · answer #10 · answered by Michael R 4 · 0⤊ 0⤋