Ariana took 2 h longer to drive 360 mi on the first day of a trip than she took to drive 270 mi on the second day. If her speed was the same on both days, what was the driving time each day?
2006-09-22 01:47:13 · 4 answers · asked by Marie 3 in Education & Reference ➔ Homework Help
Let's write this is an equation:
speed = distance/time
t = time on day 2
s = speed
s = 360 / (t+2) (because it took 2 extra hours)
s = 270 / t
If A = B and B = C, then A = C.
360 / (t+2) = 270 / t
Multiply out the bottom half of each fraction:
360 * t = 270 * (t+2)
360t = 270t + 540
90t = 540
t = 6 (so day 1 was 8 hours, solution!)
Check:
360 / 8 = 45
270 / 6 = 45 (check!)
2006-09-22 02:00:07 · answer #1 · answered by ³√carthagebrujah 6 · 0⤊ 0⤋
Formula: Distance=Rate x Time
it would be helpful if you would classfiy the information or given in a table
1st day, D= 360 mi, R= x , T= t+2
2nd day, D= 270 mi, R=x , T=t
remember the formula....D=RT
if you derive another formula to get R (rate) you would get....Rate=Distance/Time. Since Rate is the same....Distance/Time would also be the same.
the solution would go like this:
360 mi / t+2 = 270 mi / t
cross-multiplying....you would get
360t= 270t + 540
90t = 540
t=6
therefore...in the first day she traveled, 8 hours and for the second day, she traveled 6 hours
hope you understood my explanation and solution.
hope my answer is correct
2006-09-22 02:00:54 · answer #2 · answered by joan 2 · 0⤊ 0⤋
I think it took 8 hours for the 360 miles because I figured her speed out to 45 mph and divided that by 360 which = 8; and then divided 270 miles by 45mph and got 6 hours. i figured out the mph by subtracting 360 from 270 which = 90 and divided that by the 2 hours. hope its right!! I took algebra in highschool and college, so i hope i remembered something!!!
2006-09-22 02:03:49 · answer #3 · answered by jazzy 1 · 0⤊ 0⤋
depends on the road, traffic, wether conditions and what her speed was
2006-09-22 02:13:39 · answer #4 · answered by meandragon 3 · 0⤊ 0⤋