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It will be in the form of (x +or- ?)(X +or- ?)

2006-09-22 01:09:34 · 17 answers · asked by Anonymous in Science & Mathematics Mathematics

17 answers

(x+1)(x-8)

2006-09-22 01:11:29 · answer #1 · answered by Sergio__ 7 · 3 0

It is easier than anybody has said so far.

Look at the numbers before each term - they are 1, -7, and -8. They would add to zero if the sign of -7 was somehow reversed. But you can do that easily - set x to -1, and the whole thing becomes zero.

This method can even work for cubic or quartic expressions - look for the small neat value of x which makes all the positive terms cancel out the negative ones.

If the expression is zero when x = -1, then (x + 1) is a factor. So at first you write x^2 - 7x - 8 = (x + 1) (Ax + B) with the idea of solving for A and B, but you can immediately see that A = 1 otherwise the x^2 term will be wrong, and B = -8 otherwise the constant term will be wrong. These values give you the correct x term, because (x + 1) is a correct divisor - if it wasn't, then it wouldn't, but at the start we knew that it was.

Cubic and quartic and even higher expressions fall apart the same way if you start with a correct factor, based on a value which makes the expression zero. You just build up the second factor term by term until it gets to the end.

2006-09-22 03:15:48 · answer #2 · answered by Anonymous · 0 2

To factor quadratic equations like this, rewrite the equation in the form (x+ _) (x+_). Then look at the sign of the constant term. If it is positive your factors Will be of the form (x+_)(x+_) or (x-_)(x-_). Since it is negative,your factors will be (x+_)(x-_). The constants when multiplied must equal 8 so they must be either 4and 2, or 8 and 1. In these simpler types of problems you can plug in the numbers and see what works. If you do that you will end up with (x+1)(x-8). Check your work by multiplying. You get (x+1)(x-8)=x^2-8x+x-8=x^2-7x-8.

2006-09-22 03:02:47 · answer #3 · answered by True Blue 6 · 1 0

simple :
sum of factors = -7
product = -8
trial and error
so put -7 = -8 +1
x^2-7x-8 = x^2 + x -8 x -8
= x(x+1)-8(x+1)
=(x+1)(x-8)

2006-09-22 02:20:56 · answer #4 · answered by Mein Hoon Na 7 · 3 0

the attitude to do those issues is to discover factors on the most proper volume and word in the experience that they upload/subtract to the middle volume as an instance for X^2-13x+36 factors of 36.. (36*a million) (6*6) (9*4) (12*3) (18*2) you won't be able to get 13 by making use of including 36 and a million or taking 36-a million..it really is the way you attitude those issues. for this reason, 9+4 = 13 so those are those you take advantage of. next step is the signs and warning signs. you should make the signs and warning signs of 9 and four so as that in case you multiply then you extremely receives 36 and in case you upload them you receives -13 (because it truly is x^2-13, no longer x^2+13) for this reason, that's -9 and -4 because -9+-4=-13 and -9*-4 = 36 because the negatives cancel. The very last step is the parenthesis and placing the answer up (the different of the f.o.i.l. approach) merely positioned, it truly is (x-9)(x-4) <- answer a thanks to analyze if it truly is acceptable! merely FOIL the parenthesis. x*x=x^2, x*-4=-4x, -9*x=-9x, -9*-4=36 x^2-4x-9x+36 = x^2-13x+36. Voila. attempt this perspective on your different 2 issues!

2016-11-23 14:53:35 · answer #5 · answered by ? 4 · 0 0

x^2 - 7x - 8
Split 7x in such a manner that when multiply, the result is 8.
here 7x can be written as (8x - 1x). So our equation becomes:
x^2 - (8x - 1x) - 8;
x^2 - 8x +1x - 8;
x(x - 8) +1(x-8); Take (x-8) common
Hence
(x-8)(x+1)

2006-09-22 02:20:15 · answer #6 · answered by Kartik S 1 · 3 0

The x squared has no coefficient so (x )(x ).

The signs of the other two factors are different, if both positive or both negative you can't multply them to get -8. They need to add or subtract to get -7 for the middle term, so 1 and -8 are it.
(x+1)(x-8)
http://www.khake.com/page47

2006-09-22 01:22:42 · answer #7 · answered by Anonymous · 3 0

x^2 - 7x - 8
= x^2 - 8x + x - 8
= x*(X-8) +1*(X - 8)
= (X+1) * (X - 8)

2006-09-22 02:47:38 · answer #8 · answered by small 7 · 3 0

If its x to the power of something minus x minus a number, then the two brackets will be:
(x + something)(x - something)
You have to see which two numbers multiply together to make -8 (a positive number and a negative number), and then see whether those two numbers will add together to make -7.
eg -2 and +4 multiply to make -8, but added together = +2
-4 and +2 multiply to make -8 but added together = -2
-1 and + 8 multiply to make -8 but added together = +7
BUT -8 and +1 multiply to make -8 and added together = -7!
Therefore: (x -8)(x+1).

RULES:
If it's x to the power of something PLUS x PLUS a number:
(x+?) (x+?)
If it's x to the power of something PLUS x MINUS a number / If it's x to the power of something MINUS x MINUS a number:
(x+?)(x-?)
If it's x to the power of something MINUS x PLUS a number:
(x-?)(x-?)

Hope this helps!

2006-09-22 04:04:43 · answer #9 · answered by Anonymous · 1 0

(X -8) (X + 1)

2006-09-22 01:12:46 · answer #10 · answered by SLKislack 2 · 3 0

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