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Pls. answer ASAP. thanks!!!

2006-09-22 00:48:43 · 6 answers · asked by double B 2 in Science & Mathematics Mathematics

6 answers

let m-n= -7 be (i)
let m+n= 13 ne (ii)
now add (i) to (ii)

n will be eliminated and u will be left with:
2m= 6
m=3

now replace m in say, (ii)
3+n=13
n=10

therefore m=3 and n=10

2006-09-22 01:03:33 · answer #1 · answered by Minou 1 · 0 0

1) Eliminate m by subtracting (a) from (b)

gives m + n - (m - n) = 13 - (-7); 2n = 20; n = 10

2) Insert value of n in one or other of the equations

m + 10 = 13; m = 3

2006-09-22 07:56:48 · answer #2 · answered by Sadman 2 · 1 0

m - n = - 7
m = n = 13

2m = 6

2m/2 = 6/2

m = 3

The solution set is { 3 }

Insert the m value into the equation

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Solving for n

m + n = 13

3 + n = 13

3 + n -3 = 13 - 3

n = 10

The solution set is { 10 }

Insert the n value into the equation

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Check

m + n = 13

3 + 10 = 13

13 = 13

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m - n = - 7

3 - 10 = -7

-7 = -7

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The answer is

m = 3

n = 10

2006-09-22 12:08:29 · answer #3 · answered by SAMUEL D 7 · 0 0

m-n=-7
m+n=13
2m+n-n=6
2m=6 => m=3
3-n=-7 => n=10

2006-09-22 11:21:15 · answer #4 · answered by Lokman s 1 · 0 0

add both equations, 2m=6 means m=3
Subtract second equation from first, -2n=-20 means n=10

Solution set is, m=3, n=10.

2006-09-22 07:50:39 · answer #5 · answered by Anonymous · 0 0

m-n= -7.............(1)
m+n = 13...........(2)
adding (1) and (2) 2m = 6 so m=3
from (2) n = 13-m = 13- 3 = 10

2006-09-22 08:04:34 · answer #6 · answered by saby 2 · 0 0

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