let m-n= -7 be (i)
let m+n= 13 ne (ii)
now add (i) to (ii)
n will be eliminated and u will be left with:
2m= 6
m=3
now replace m in say, (ii)
3+n=13
n=10
therefore m=3 and n=10
2006-09-22 01:03:33
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answer #1
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answered by Minou 1
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1) Eliminate m by subtracting (a) from (b)
gives m + n - (m - n) = 13 - (-7); 2n = 20; n = 10
2) Insert value of n in one or other of the equations
m + 10 = 13; m = 3
2006-09-22 07:56:48
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answer #2
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answered by Sadman 2
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m - n = - 7
m = n = 13
2m = 6
2m/2 = 6/2
m = 3
The solution set is { 3 }
Insert the m value into the equation
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Solving for n
m + n = 13
3 + n = 13
3 + n -3 = 13 - 3
n = 10
The solution set is { 10 }
Insert the n value into the equation
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Check
m + n = 13
3 + 10 = 13
13 = 13
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m - n = - 7
3 - 10 = -7
-7 = -7
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The answer is
m = 3
n = 10
2006-09-22 12:08:29
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answer #3
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answered by SAMUEL D 7
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m-n=-7
m+n=13
2m+n-n=6
2m=6 => m=3
3-n=-7 => n=10
2006-09-22 11:21:15
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answer #4
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answered by Lokman s 1
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add both equations, 2m=6 means m=3
Subtract second equation from first, -2n=-20 means n=10
Solution set is, m=3, n=10.
2006-09-22 07:50:39
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answer #5
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answered by Anonymous
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m-n= -7.............(1)
m+n = 13...........(2)
adding (1) and (2) 2m = 6 so m=3
from (2) n = 13-m = 13- 3 = 10
2006-09-22 08:04:34
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answer #6
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answered by saby 2
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