math extra credit?

Question

Given the equation x^3 - 2x^2 + x - 3 = 0, find an equation whose roots are each 2 less than the roots of the given equation.

Answer 1

Just replace each x with an (x+2).

(x+2)^3 - 2(x+2)^2 + (x+2) - 3 = 0.

If you want, you can multiply out the parentheses and simplify.
(x^3+6x^2+12x+8) -2(x^2+4x+4) +x-1 = 0
x^3 + 4x^2 + 5x -1 = 0

Answer 2

x^3-8x^2+21x-21=0