A+1.60xA+1/3x1.6xA = 47 SOLVE FOR A?

Answer 1

A+1.60xA+1/3x1.6xA = 47

A + (1.60xA) +[1/3 x (1.6xA)] = 47

So put in the brackets to seperate them and always remember multiply and divisions before additions and subtraction!

A + 1.6A + (1/3 x 1.6A) = 47

A + 1.6A + 8/15A = 47

Add up all the coefficients!

(1 + 1.6 + 8/15)A = 47

47/15A = 47

therefore 47 x 15/47 = A
therefore A = 15!

Answer 2

A = 15

Answer 3

A + (1.60*A) + (1/3 * 1.6 *4) =47

ur question is easily understood if written in that way bcoz they is no contraversial between letter x and multiplication sign.

so A +1.6A + 1.6A/3 = 47
to deal away with th 3 in the denominator u can just divide normally, look for LCM or multiply each section by 3.
I'll choose the latter A*3 + 1.6A*3 + (1.6A/3)*3 = 47*3

3A + 4.8A + 1.6A = 141

add all the like terms 9.4A = 141

divide both sides by 9.4 = 9.4A/9.4 = 141/9.4

A=15

Answer 4

15

Answer 5

Tell me, what grade r u in?
this question is really simple...
add up all ur A's and divide 47 with the figure u get in front of A
(in the case of 2A, take 47/2=A, juz an example)

Answer 6

A=47/(1+1.60+1.6/3)
The rest is up to you. How old are you? 3?

Answer 7

Your statement of the problem is ambiguous. I can see 2 possibilities:
A*(1+1.6*(1+1/3)) = 47

and

A(1+1.6) +1/(3*1.6*A) = 47
3*1.6*(1+1.6)*A^2 + 1 = 47

both are easily solved.

Answer 8

If its ur homework, i wudnt help. DO IT YOURSELF!!!
but i'll definitely try. if i get the answer, i'll let u know, 4 that, gimme ur email id or whatever

Answer 9

A+1.6A+1/3*1.6A=47
A=15
Why do you ask this?