2006-09-21 19:43:21 · 18 answers · asked by siany warny 4 in Science & Mathematics ➔ Mathematics
it sounds like your trying to break into a breifcase or sumthing lol
2006-09-21 20:53:26 · answer #1 · answered by steve 2 · 5⤊ 7⤋
From 0 - 9 there are altogether 10 numbers.
0, 1, 2, 3, 4, 5, 6, 7, 8, 9
Since you must find the number of possible 3 digit cimbinations, then you take 10^3
10^3 = 10x10x10 = 1000
Therefore, there are 1000 possible combinations (:
2006-09-21 23:14:31 · answer #2 · answered by b0b0link 2 · 2⤊ 0⤋
How Many Combinations With 3 Numbers
2016-10-03 11:08:36 · answer #3 · answered by ? 4 · 0⤊ 0⤋
RE:
how many possible 3 digit combinations are there from 0-9?
2015-08-02 00:27:16 · answer #4 · answered by Anonymous · 0⤊ 0⤋
Think about forming one of the three digit numbers. If the digits are allowed to repeat then you can choose any of the ten digits as the first digit, and once that is chosen you can choose any of the ten digits for the second digit, and again once the first two are chosen you can choose any of the ten digits as the final digit. Thus the number of ways you can form the three digit number is
10 10 10 = 1000.
If the digits cannot repeat then, again you can choose any of the ten digits for the first digit, but once that is chosen you can only chose the second digit from the nine remaining, and once the first two are chosen you can choose the final digit from the eight remaining. Thus the number of ways you can form the three digit number is
10 9 8 = 720.
Hope this helps,
2006-09-21 20:14:09 · answer #5 · answered by Red 1 · 2⤊ 0⤋
There are 2 ways
Digit repeating 100 to 999 that is 900 numbers
digit not repeating(ist digit 9 ways, cannot be zero, second 9 ways and 3rd 8 ways so 9*9*8 = 648.
2006-09-22 00:00:02 · answer #6 · answered by Mein Hoon Na 7 · 0⤊ 1⤋
There are 1000 three digit combination. Here the order matters, so for example 233 is different from 323 which is different from 332, etc.
2006-09-21 19:47:14 · answer #7 · answered by Kala 1 · 1⤊ 0⤋
10^3=1000
if u r inlcuding 000 as a combination
another way of looking at it is "all the numbers from 0 to 999", since 1000 has four digits and does no longer satisfy the conditions
2006-09-21 21:37:10 · answer #8 · answered by babeladitya 1 · 2⤊ 1⤋
1 digit - 10 possible values
2 digits - 100 possible values
3 digits - 1.000 possible values
4 digits - 10,000 possible values
5 digits - 100,000 possible values
6 digits - 1,000,000 possible values
7 digits - 10,000,000 possible values
8 digits - 100,000,000 possible values
In other words
n digits = 10^n possible values
2006-09-21 19:49:34 · answer #9 · answered by Walter W. Krijthe 4 · 8⤊ 0⤋
10 X 10 X 10=1,000.
2006-09-21 19:46:48 · answer #10 · answered by Professor Armitage 7 · 1⤊ 0⤋
10*10*10
2006-09-21 19:53:18 · answer #11 · answered by Helmut 7 · 0⤊ 1⤋