Can a vacuum in a container or balloon stay stable with a resistance ring?

Question

I have discovered a higher level of this subject and each day find out more and more. So the thought is since a vacuum in a balloon will easily float better then helium if it is sustained then will it be able to sustain with a resistance ring? A vacuum evacuates too quickly because the weight of air is dominant and causes pressure to the container of the vacuum so it shrivels up. But would a container of vacuum inside a container of helium be able to sustain enough resistance long enough for them to react to lift?

Answer 1

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What on Gods Earth *have* you been smoking?
And did you bring anough to share?

Anyway, all technobabble aside, the amount of material required to withstand atmospheric pressure would far outmass the amount of air it displaced. (Unless, of course, it was machined out of a single, solid piece of unobtainium ☺)


Doug

Answer 2

You are wrong. Consider Helium container you are discussing. Let us assume Helium container is just another baloon with no hard material. It needs to be pressurised just equal to the atmospheric pressure so that it can withstand the air pressure. Putting another balloon inside this balloon means you are again pushing the inner balloon with same force as air, though with helium gas.

Bottomline is, it is not the type of gas which affects how long the vaccuum lasts. It is the pressure of the gas which matters.

Answer 3

To create lift the container must weigh less than the air displaced. Helium in a balloon is still surrounded by air at atmospheric pressure of 14.7 psi so the helium must exert 14,7 psi and the container must withstand 14.7 psi. A surface area 12 inches by 12 inches at 14.7 psi would have a force of 2116 lb on it.
If you solve this problem and find a material strong enough you would be a genius.