A football stadium has 20000 seats between the goal lines and 5000 in the end zones. An end-zone seat is $5 cheaper than one between the goal lines. For one game, the revenue when all seats were sold was $350000. What is the cost of each type of seat?
2006-09-21 18:24:57 · 3 answers · asked by Lana 1 in Science & Mathematics ➔ Mathematics
Let C be the cost of an end zone seat. Then C+5 is the cost of a seat between the goal lines.
20000 (C+5) + 5000 C = 350000
Solve for C
2006-09-21 18:29:57 · answer #1 · answered by z_o_r_r_o 6 · 0⤊ 0⤋
Let x be the price of seat between goal lines, then
Let y be the price of seat in the end zone
We have 2 equations,
20000x + 5000y = 350000 .....(1)
x = y + 5 .....(2)
Put (2) into (1),
20000(y+5) + 5000y = 350000
20000y + 100000 + 5000y = 350000
25000y = 250000
y = 10 .....(3)
Put (3) into (2),
x = 10 + 5
x = 15
Therefore,
The price of seat between goal lines is $15, and the price of seat at end zone is $10.
2006-09-22 01:34:47 · answer #2 · answered by davidkwankwokfai 3 · 0⤊ 0⤋
$15 and $10 respectively
2006-09-22 01:30:13 · answer #3 · answered by Chris™ 5 · 0⤊ 0⤋