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Lead metal is produced by heating solid lead(II) sulfide with solid lead(II) sulfate, resulting in liquid lead and sulfur dioxide gas. Write a balanced equation for the reaction using complete formulas for the compounds with phase labels.
Pb2S(s) + Pb2SO4= 4Pb(l)+2SO2

2006-09-21 16:42:41 · 6 answers · asked by Anonymous in Science & Mathematics Chemistry

6 answers

Your equation should be

PbS + PbSO4 --> 2Pb(l) + 2SO2(g)

2006-09-21 18:30:10 · answer #1 · answered by rviteri 2 · 1 0

Lead(II) sulfate means that the formal charge on the Pb is +2. The sulfate ion has a formal charge of -2, so the formula for lead(II) sulfate is PbSO4 (not Pb2SO4).

(There is also a lead(IV) sulfate. In this salt, the lead has a formal charge of +4, so the formula would be Pb(SO4)2. As far as I know, there is no Pb(I) sulfate, which would be the name for the formula you were using.)

Similarly, the charge on the sulfide ion in lead(II) sulfide is -1, so the formula for this compound sould be PbS2 (not Pb2S).

Use these formulas in your reaction and rebalance it.

2006-09-21 16:50:11 · answer #2 · answered by hfshaw 7 · 1 0

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2016-12-15 12:05:21 · answer #3 · answered by rothe 3 · 0 0

ROFLMAO.

You're not getting a scholarship, now are you?

Okay, here's what your'e doing wrong: expecting someone to actually answer that.

Next stop, the library.

2006-09-21 16:50:17 · answer #4 · answered by Manuel L 5 · 0 2

have you ever tried the chemistry or physics even calculus page for your problems? this is not the place for you okay?

2006-09-21 16:47:13 · answer #5 · answered by vanessa 6 · 0 2

That makes me want to throw up.

2006-09-21 16:49:45 · answer #6 · answered by Amanda 4 · 0 2

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