2006-09-21 16:14:19 · 15 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
u add like terms: xy+2x
2006-09-21 16:16:30 · answer #1 · answered by Anonymous · 1⤊ 0⤋
You should give me 10 points.... this is how it works.
14xy - 6x -7xy + 8x - 6xy = 0 ; (if the whole equation is = 0)
because a equation must be equal to something.. cannot be standalone.
Rearrange them so you will not get confuse is:
14xy - 7xy - 6xy -6x +8x = 0
xy + 2x = 0
x(y+2) = 0 ..., this could be your answer
x = 0 or y = -2 ... this is the most simplify answer if the whole equation = 0
2006-09-21 16:58:03 · answer #2 · answered by Mr. Logic 3 · 0⤊ 1⤋
you get the "like" terms (any numbers with the same letters following) and combine them
eg. 14xy-7xy-6xy which = xy
then, you do it to the other 2 "like" terms so
-6x+8x= (positive) 2x
what do you end up with? =xy+2x
14xy-6x-7xy+8x-6xy = xy+2x
P.S the terms include the + or - sign that come before it. eg. the first term is 14xy and the second term is -6x
2006-09-21 16:26:05 · answer #3 · answered by Anonymous · 0⤊ 0⤋
like terms
xy+2x
{14xy, -7xy, -6xy} are all like terms because the all contain the variables xy, now if it was xy^2 that'd be different, but it doesn't so we're gonna skim past that, now you add all those together, ignoring the variables and just adding the constants, so 14-7-6=1
{-6x, 8x} like terms, same thing, -6+8=2
2006-09-21 16:17:53 · answer #4 · answered by Archangel 4 · 0⤊ 0⤋
14xy - 6x - 7xy + 8x - 6xy (gather like terms)
=14xy - 7xy - 6xy -6x + 8x (calculate like terms)
=xy +2x (this may be the ans or go further and take out the common term x)
=x(y+2)
2006-09-21 16:21:49 · answer #5 · answered by KAT 2 · 0⤊ 0⤋
xy +2x
You take the three xy parts (14xy -7xy -6xy) and get 1*x*y or xy.
You do the same for x (-6x + 8x) and get 2x.
To further complete the simplification, factor out the x to get
x*(2+y).
Your done at this point
2006-09-21 16:18:26 · answer #6 · answered by messagetothefish 2 · 0⤊ 0⤋
14xy - 6x - 7xy + 8x - 6xy
(14xy-7xy-6xy) - (6x+8x) ....group the xys and the xs
xy + 2x......do the subraction and addiction of the same groups
x(y+2)....take x out---common factor
2006-09-21 16:18:30 · answer #7 · answered by Anonymous · 0⤊ 0⤋
14xy - 6x - 7xy + 8x - 6xy
14xy - 7xy - 6xy -6x + 8x
xy + 2x = x (y + 2)
2006-09-21 21:58:11 · answer #8 · answered by just me 4 · 0⤊ 0⤋
properly first of all cancel out any exponents...a y from the the two cancels out so which you have... -7xy/28x^5 then do your x's -7y/28x^4 now do your numbers what number situations does 7 bypass into 28? 4 situations -y/4x^4 counting on your instructor they could ask you to the two positioned impressive or backside as unfavourable and likewise write it so as that all and sundry numbers are up impressive. in my adventure my instructor could prefer... -(a million/4)yx^-4 i think of it is so ordinary because it is going.
2016-10-17 10:29:45 · answer #9 · answered by ? 4 · 0⤊ 0⤋
Combine the xy's and the x's. the answer is xy +2x.
2006-09-21 17:12:26 · answer #10 · answered by xm4 2 · 0⤊ 1⤋