2006-09-21 15:58:46 · 9 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
54 divided by 3 is 18.
Hence, the consecutive integers are 17, 18, and 19.
2006-09-21 16:01:27 · answer #1 · answered by Bramblyspam 7 · 2⤊ 0⤋
The easiest way to get the answer to this question is to take 54 and divide by 3. The answer is 18. That will be the number that goes in the middle_____,18,_____. Since the numbers are consecutive the numbers must be 17,18,19.
2006-09-21 16:42:19 · answer #2 · answered by Dreana S 2 · 0⤊ 0⤋
The three consecutive integers are 17, 18 and 19.
done
2006-09-21 16:02:55 · answer #3 · answered by Leo J 3 · 0⤊ 1⤋
17 18 19
2006-09-21 16:01:36 · answer #4 · answered by Archangel 4 · 0⤊ 1⤋
Simple, assign them as x, x+1, and x+2. Now put it as x+(x+1)+(x+2)=54. You get 3x+3=54. That gives you x=17. That means the #'s are 17,18, and 19
2006-09-21 16:02:35 · answer #5 · answered by MateoFalcone 4 · 1⤊ 0⤋
integer 1 = x
integer 2 = x+1
integer 3 = x + 1 + 1 = x+2
x + x + 1 + x + 2 = 54
3x + 3 = 54
3x = 51
x = 17
17,18,19
2006-09-21 16:01:13 · answer #6 · answered by Scott S 2 · 1⤊ 0⤋
17, 18, and 19 because:
x + (x + 1) + (x + 2) = 54
solve for x, and figure out the next two numbers by adding one to each
2006-09-21 16:01:39 · answer #7 · answered by joeyschiliro 2 · 1⤊ 0⤋
17,18,19
2006-09-21 16:02:40 · answer #8 · answered by Dr M 5 · 0⤊ 1⤋
17,18,19
2006-09-21 16:02:26 · answer #9 · answered by mystic_golfer 3 · 0⤊ 1⤋