2006-09-21 13:58:30 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Ok. Let's call the length L and the width W.
L = 1.75 * W
Area = 2268 = L * W
2268 = (1.75 * W) * W
2268 = 1.75 * W^2
1296 = W^2
36 = W
L = 1.75 * 36 = 63
So, width = 36 and length = 63
2006-09-21 13:59:50 · answer #1 · answered by nondescript 7 · 0⤊ 1⤋
Let the width be d.
Then, (7/4)*d^2 = 2268
Or, d^2 = 1296
Or, d = 36; (7/4)*d = 63
Hence, the length and width are respectively 63 feet and 36 feet.
2006-09-22 10:25:34 · answer #2 · answered by K Sengupta 4 · 0⤊ 0⤋
x=width
1.75x=length
Area = 2268 square feet
Area = Length * width
2268 = 1.75x * x
2268 = 1.75x^2
Divide by 1.75 on both sides
1296 = x^2
x = square root of 1296
x = 36
So the width is 36 feet
The width is 1.75*36 feet, or 63 feet.
Check by multiplying out again:
36*63=2268 [checks!]
2006-09-21 21:06:48 · answer #3 · answered by apnate 3 · 0⤊ 0⤋
1. L(ength) = W(idth) * 1.75
2.. L * W = 2268
so we got,
W*W*1.75=2268
then,
W=root of square 2268/1.75=36
Goal! L = 36*1.75=63
The length is 63 ft and the width is 36 ft.
2006-09-21 21:13:12 · answer #4 · answered by Billy 2 · 0⤊ 0⤋
A = W*L
2268 = W*L
2268 = W*(1.75*W) [since L = 1.75*W]
2268 = 1.75*W^2
W^2 = 1296
W = 36 [you actually get + and - roots, but negative width is meaningless]
L = 63 [since L = 1.75*W]
2006-09-21 21:01:49 · answer #5 · answered by Anonymous · 1⤊ 0⤋