y=3x-2
2006-09-21 13:05:23
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answer #1
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answered by Anonymous
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3x-y=2
3x=2+y
x=2+y/3
if y=1 then x=2 1/3 and so on
2006-09-21 13:17:47
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answer #2
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answered by jymde 1
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hum..
3x-y=2 add y and and divide both sides of equation by 3.
x=1/3y+2/3
then use substitution on the origanal equation.
3(1/3y+2/3)-y=2
3y+2-y=2
2y+2=2
2y=0
y=0
substitution again to find x.
3x-0=2
x= 2/3
the answer is X=2/3 and y=0 or (2/3,0)
to prove: 3*2/3-y=2, so y would equal 0
and
3x-0=2, so X would equal 2/3
so
3*2/3-0=2. Correct.
but also, if X=1, Also Y=1. 3*1-1=2
2006-09-21 13:19:08
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answer #3
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answered by Rockachopa 1
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This Site Might Help You.
RE:
solve the equation 3x-y=2?
2015-08-10 11:26:43
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answer #4
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answered by Anonymous
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To solve two variables you need two equations and not one. May be the asker expecting:
3x=2-y and so x= (2-y)/3
and y=3x-2
Anyway that is my answer.
2006-09-21 13:07:16
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answer #5
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answered by Rammohan 4
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This equation can't be solved! You can use it to find the x and y intercepts. Also, it can be rearranged to isolate either x or y, which is what I'm assuming you meant.
Here's how to isolate the variables:
y = 3x-2
or
x = (2 + y)/3
2006-09-21 13:08:07
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answer #6
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answered by عبد الله (ドラゴン) 5
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set x=0
3x=y+2
x= (y+2)/3
2006-09-21 13:05:44
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answer #7
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answered by Anonymous
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1. subract 3x from both sides and get -y= -3x+2
2. multiply everything by 2 and get y=3x+2
2006-09-21 13:11:39
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answer #8
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answered by Anonymous
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x=1 and y=1
2006-09-21 13:05:56
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answer #9
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answered by Anonymous
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y=3x -2
2006-09-21 13:05:47
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answer #10
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answered by rod_dollente 5
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