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6 answers

The probability of a completely random stranger's birthday being on a Saturday = 1/7

The probability of that event NOT occuring three times = (6/7)^3

2006-09-21 12:11:45 · answer #1 · answered by Baseball Fanatic 5 · 1 0

probability= number of ways the outcome can happen ^ total number of possible outcomes

therefor probability= 1/7 (saturday is one day of the 7 day of the week)

= 0.14

and the probability of that NOT happening for the three people is = (6/7)^3

= 0.285

2006-09-21 19:16:25 · answer #2 · answered by FreeVoice 2 · 0 2

6/7*6/7*6/7 = 216/343 or about 63% likely.

2006-09-21 19:11:05 · answer #3 · answered by Cabhammer 3 · 0 1

Counter question 1: What campus?

2006-09-21 19:09:04 · answer #4 · answered by pito16places 3 · 0 4

6/7*6/7*6/7=0.63

2006-09-21 19:09:41 · answer #5 · answered by Anonymous · 3 1

(6/7)^3=62.9%

2006-09-21 19:13:15 · answer #6 · answered by bruinfan 7 · 1 0

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