L = 2W
P = 2L + 2W
48 = 2(2W) + 2W
48 = 4W + 2W
48 = 6W
8 = W
L = 2(8) = 16
2006-09-21 10:28:33
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answer #1
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answered by MsMath 7
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Length = L
Width = W
L=2W or L = W + W (given in the problem)
L + L + W + W = 48 (rule for rectangles)
Substitute the L's for W's to only have one variable.
2W + 2W + W + W = 48
6W = 48 (simplified)
W = 8 (48/6=8)
L= 2(8)
L=16
2006-09-21 17:34:04
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answer #2
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answered by Lady 5
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Well, let's call its width x. Therefore its length is 2x. So, going around the perimeter, we'll have an x, a 2x, another x, then another 2x for a total of 6x. If 6x = 48 then x = 48/6 or 8. Right? So width is 8, length is 16.
2006-09-21 17:29:49
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answer #3
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answered by All hat 7
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Okay, you know you have a piece of wire 48m long, and the length is twice as long as the width. So... you have to take one width as x, since you know the length is twice the width, the length becomes 2x. Now add up all the sides, so that would be x+x+2x+2x=6x. Now it would be 6x=48m. Solve for X. x=8, remember x is the width, and length is twice as long, so the length is 16.
2006-09-21 17:34:34
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answer #4
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answered by B-B@!! P!@Y@ 4
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x = width of 1 side
2x = length of 1 side
x + 2x + x + 2x = 48
6x = 48
x = 8
2x = 16 = length = 16 meters
check work: 8 + 16 + 8 + 16 = 48
2006-09-21 17:32:01
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answer #5
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answered by Steve P 5
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let the width of the rctangle be x
length=2x
the equation
x+2x+x+2x=48m
6x=48m
x=8m
so the length is 16m and the width 6 m
check
perimeter=lrngth of the wire
p=2(l+w)
48=2(16+8)
checks
2006-09-21 17:30:39
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answer #6
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answered by raj 7
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Length: Try Calculator
Width: Try the actual calculator!!
2006-09-21 17:30:38
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answer #7
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answered by Head Master 2
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2w + 2l = 48
l = 2w
3l = 48
l = 16
w = 8
2006-09-21 17:30:50
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answer #8
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answered by bob h 3
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L = 2W
48 = (L + W)*2 = (3W)*2 = 6W
W = 8
L = 2W = 16
2006-09-21 17:30:09
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answer #9
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answered by en_vacances 7
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