The labour costs for a certain project were $3345 per day for 17 technicians and helpers. If the technicians earned $210/day and the helpers $185/day, how many technicians were employed on the project?
2006-09-21 10:04:55 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Number of technicians=x ; helpers=y
x+y=17 ; y=17-x
x*210+y*185=3345
x*210+(17-x)*185=3345
25*x+3145=3345
x=8
2006-09-21 10:12:21 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Guess and Check.
$3345 - 210(8) = $1665
$1665 divided by 9 = $185
technicians = 8
helpers = 9
2006-09-21 17:41:59 · answer #2 · answered by calebrules1991 5 · 0⤊ 0⤋
17
2006-09-21 17:13:52 · answer #3 · answered by Anonymous · 0⤊ 0⤋
let the wages of the technicians and labour be x and y respectively
the equations
210x+185y=3345
x+y=17
210x+210y=3570
subtracting
25y=225
y=9
substituting
x=8
so 8 technicians and 9 labour were employed
2006-09-21 17:15:17 · answer #4 · answered by raj 7 · 0⤊ 0⤋
two variable, two equations
x: # of technicians
y: # of helpers
x + y = 17
210 * x + 185 * y = 3345
2006-09-21 17:08:07 · answer #5 · answered by danthemanbrunner 2 · 0⤊ 0⤋
how many engineers?
how many mechanics?
1 engineer=5aides
1 mechanic=1aide
2006-09-21 17:12:20 · answer #6 · answered by gussie r 3 · 0⤊ 0⤋