Dividing Rational Expressions: 12x^3y^2z^5/7a^2b^3c^5 ÷ 18x^5y^2z^3/35a^3b^2c^2?

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2006-09-21 09:12:12 · 4 answers · asked by caleb m 1 in Education & Reference ➔ Homework Help

rule is (a/b)/(c/d)=ad/bc
the expression
=12x^3y^2z^5*35a^3b^2c^2/7a^2b^3c^5*18x^5y^2z^3
(10/3)(x^-2z^2ab^-1c^-3)
10az^2/3x^2bc^3

2006-09-21 09:22:58 · answer #1 · answered by raj 7 · 0⤊ 0⤋

Answering that isn't worth 2 points, i'll tell u that

2006-09-21 16:19:19 · answer #2 · answered by Anonymous · 0⤊ 0⤋

Do your own homework!

2006-09-21 16:19:08 · answer #3 · answered by Anonymous · 0⤊ 0⤋

no help in homeworks...............

2006-09-21 16:24:44 · answer #4 · answered by Pummi 4 · 0⤊ 0⤋