2006-09-21 09:04:17 · 8 answers · asked by airjames023 1 in Science & Mathematics ➔ Chemistry
Only one. The 0s after the decimal point(but b4 the no.) do not count..imagine if u were 2 put that as 3 significant figures..wud u put 0.00? Nop coz ud put 0.00400 only the zeros after the 1st number count
0.03 to 2 sf would would be 0.030 (the zero after the 3 must b there) and 0.00000444 to 2 sf would b 0.0000044 just some examples.
2006-09-22 09:42:50 · answer #1 · answered by jo88 2 · 0⤊ 0⤋
a quantity is divisible by using 9 if and on condition that the sum of the digits is divisible by using 9. If we could continuously use all 4 numbers as quickly as and merely as quickly as, then there is not any answer because of the fact the sum of the digits could continuously be 3+4+5+6 = 18. If we are allowed to repeat digits, then the main important quantity we are in a position to make is 6666, the sum of whose digits is 24. that may no longer divisible by using 9, subsequently the respond is 6666.
2016-12-12 12:30:10 · answer #2 · answered by ? 4 · 0⤊ 0⤋
3 because zeros after a decimal but before a number other than zero count as significant digits
2006-09-21 09:12:48 · answer #3 · answered by Anonymous · 0⤊ 0⤋
Three 0's after the decimal place count
2006-09-21 09:06:50 · answer #4 · answered by Silentspeedster 2 · 0⤊ 0⤋
i because any zero if it is after a decimal point and a number is not before it is not a significant digit
good luck
2006-09-21 09:07:59 · answer #5 · answered by Eca 1 · 0⤊ 0⤋
Three
2006-09-21 09:06:32 · answer #6 · answered by Joseph G 3 · 0⤊ 0⤋
Three, because every digit is essential in order to specify the quantity. .0040 would still have three, as would 0.004 because in these cases one of the three zeros is not essential to specify the quantity.
2006-09-21 09:13:39 · answer #7 · answered by PaulCyp 7 · 0⤊ 0⤋
sigfigs are stupid
2006-09-21 09:15:37 · answer #8 · answered by tubasteve 2 · 0⤊ 0⤋