3/7 x + 5/9 y = 27
and
1/9 x + 2/7 y= 7
Why are these two equations aked in the same question? Are there inequalities? I don't get this.
2006-09-21 08:36:42 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
x = 63
y = 0
2006-09-21 08:43:58 · answer #1 · answered by Keex 2 · 0⤊ 0⤋
First off, you should go to class. The fact that you are do confused at what to do seems like you aren't learning anything.
First, solve for one factor in an equation (multiply by 63 to get ride of fractions):
27x + 35y=1701
x=63-35/27y
then put this into the second equation:
1/9(63-35/27y) + 2/7y = 7
then solve for y, then put this y value back into the first equation and solve for x.
2006-09-21 08:49:12 · answer #2 · answered by Take it from Toby 7 · 0⤊ 0⤋
They want you to find all the values of x and y that will make both equations true.
I recommmend starting by multiplying both equations by 63 to get rid of the fractions.
2006-09-21 08:41:32 · answer #3 · answered by Demiurge42 7 · 0⤊ 0⤋
7x9=63
2006-09-21 09:45:09 · answer #4 · answered by gussie r 3 · 0⤊ 0⤋
You obviously do not know what you are talking about.
2006-09-21 11:13:56 · answer #5 · answered by calebrules1991 5 · 0⤊ 0⤋