Cobalt(II) sulfate heptahydrate has pink-colored crystals. When heated carefully, it produces cobalt(II) sulfate monohydrate, which has red crystals. If 3.542 g of the heptahydrate yields 2.119 g of the monohydrate, how many grams of the anhydrous cobalt(II) sulfate could be obtained?
2006-09-21 04:55:32 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
1.882 gms
Soln
Hepta is 7 & mono is 1 so 7atoms of water to 1 is 6 total wieght diference wass 3.542 -2.119 = 1.423... per atom of water 1.423/6 = .237 & with out water will be 2.119 - .237 = 1.882 gms
2006-09-21 05:04:26 · answer #1 · answered by Ashish Samadhia 3 · 0⤊ 0⤋
First, find the difference in the mass of the heptahydrate and the mononhydrate.
Then, divide that value by 6.
With the value you've divided, subtract it from the mass of the monohydrate.
I think so.
2006-09-21 11:59:24 · answer #2 · answered by meiqi_87 2 · 0⤊ 0⤋
Mass of water released = 3.542-2.119 g = 1.323 g
Moles of water = 0.0735 mol
So, one sixth of this must be released more so, mass of water to be released = 0.0735*18/5 = 0.2646 g
Thus , anhydrous CoSO4 (Cobalt (II) Sulphate) = 2.119 - 0.2646 g = 1.8544 g
2006-09-21 12:13:07 · answer #3 · answered by ag_iitkgp 7 · 0⤊ 0⤋