formula for nitric acid is HNO3
2006-09-21 04:51:34 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
First, find the molecular weight of HNO3 (1.0078 + 15 + 3(15.99)).
Then, divide the mass of HNO3 by the molecular weight to get the number of moles.
Then, using the avogadro constant: 6.0221415×1023 atoms/mole,
multiply that with your number of moles obtained.
2006-09-21 04:57:06 · answer #1 · answered by meiqi_87 2 · 0⤊ 0⤋
Molar mass of HNO3 = (1+14+3*16)g = 63g
So, 2.69 g -> 2.69/63 moles
In one mole of HNO3, O atoms = 3 moles
So, in 2.69/63 mol, O atoms = 2.69*3/63 mol = 0.128 mol
2006-09-21 12:04:34 · answer #2 · answered by ag_iitkgp 7 · 0⤊ 0⤋
molecular weight of HNO3=1+1+48=50
wt of O in 2.69 g of nitric acid=2.69/50
16 gms of oxygen has 6.022*10^23 atoms
so 2.69/50 g=2.69/50(6.022*10^23) atoms
2006-09-21 11:56:58 · answer #3 · answered by raj 7 · 0⤊ 0⤋