help with inequality problem. please help. its urgent?

Question

How do I solve the inequality of square root of m^2>2?

Answer 1

m^2>2
m>-2 or m<2

Answer 2

all of us understand that each and everyone sq. numbers are valuable. shall we take any 2 arbitrary valuable actual numbers a and b. Then: (?a - ?b)^2 >= 0 a - 2?(ab) + b >= 0 a + b >= 2?(ab) word that in case you divide the two factors by potential of two, you get the A.M. G.M inequality, (a + b)/2 >= ?(ab). whilst a = p and b = 2: p + 2 >= 2?(2p) whilst a = q and b = 2: q + 2 >= 2?(2q) whilst a = p and b = q: p + q >= 2?(pq) Now, as p + 2 >= 2?(2p), q + 2 >= 2?(2q) and p + q >= 2?(pq), we've: (p + 2)(q + 2)(p + q) >= 2?(2p) * 2?(2q) * 2?(pq) We get this by potential of purely multiplying the left hand factors and the right hand factors off all the three equtions at the same time. So: (p + 2)(q + 2)(p + q) >= 8?(p^2 * q^2 * 2^2) (p + 2)(q + 2)(p + q) >= 8 * p * q * 2 (p + 2)(q + 2)(p + q) >= 16pq Q.E.D desire this enables.

Answer 3

Take the square root of both sides. Then add the plus/minus in front of the square root of 2 to make sure that you have both answers for m.

Hope this helps. Good Luck.

Answer 4

m^2>2
m>sqroot(2) or m<-sqroot(2)

this can be derived by using the graph, y =x^2-2, taking the m to be x.

den, you see the portion of graph where y>0 and you get your range for x, i.e x^2-2>0. (:

Answer 5

m^2>2
m>+2 or m<2

Answer 6

i dont know but with this answer i got to level 2.

thanks!

Answer 7

I tried, I got nothin', good luck!

Answer 8

http://hotmath.com/index.html?referrer=google-m