63/3=21 is the middle no
so the nosare 20,21 and 22
2006-09-21 03:27:19
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answer #1
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answered by raj 7
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20 21 22
2006-09-21 03:28:36
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answer #2
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answered by one8swayze 2
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20 21 22
2006-09-21 03:28:18
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answer #3
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answered by alanc_59 5
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Use linear equations to solve
Take nos as x, x+1 and x+2
So x+x+1+x+2=63
or x=20
So the nos are 20,20+1 and 20+2 ie 20,21 and 22
Or else for the answer in seconds divide 63/3 to get the middle value. But the first answer is more technically correct
2006-09-21 05:55:43
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answer #4
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answered by Anand 2
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Let first number = x, let second number = x + 1, let third number = x + 2.
x + (x + 1) + (x + 2) = 63
3x + 3 = 63 (Subtract 3 from each side)
3x = 60 (Divide both sides by 3)
x = 20
The numbers are 20, 21, and 22.
QED
2006-09-21 07:29:42
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answer #5
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answered by CSUFGrad2006 5
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20, 21 and 22
2006-09-21 03:27:32
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answer #6
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answered by Jemima 3
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x +(x+1)+(x+2) = 63
x+3 =63
x= 63-3. =60=3x
x=20.
20, 21,23 are three successive numbers whose sum is 63.
2006-09-21 03:33:07
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answer #7
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answered by J.SWAMY I ఇ జ స్వామి 7
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X + (X + 1) + (X + 2) = 60
X + X + X = 60 - 1 - 2
3X = 60
X = 20
20 + 21 + 22 = 63
I hope I explained it - better than just giving you the answer.
2006-09-21 03:29:46
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answer #8
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answered by eeaglenest 3
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x+(x+1)+(x+2)=63
3x+3=63
3x=60
x=20
x+1=21
x+2=22
So the consecutive integer series is 20,21 & 22.
2006-09-21 03:58:55
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answer #9
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answered by miyuki & kyojin 7
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Let one number be x.
Other two number will be x+1, x+2
According to the question,
x+x+1+x+2=63
3x+3=63
3x=60
x=20
Therefore, one number = 20
Other two numbers are 21,22.
2006-09-21 03:33:39
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answer #10
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answered by noesis 2
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