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18 answers

63/3=21 is the middle no
so the nosare 20,21 and 22

2006-09-21 03:27:19 · answer #1 · answered by raj 7 · 1 0

20 21 22

2006-09-21 03:28:36 · answer #2 · answered by one8swayze 2 · 0 0

20 21 22

2006-09-21 03:28:18 · answer #3 · answered by alanc_59 5 · 0 0

Use linear equations to solve
Take nos as x, x+1 and x+2
So x+x+1+x+2=63
or x=20
So the nos are 20,20+1 and 20+2 ie 20,21 and 22
Or else for the answer in seconds divide 63/3 to get the middle value. But the first answer is more technically correct

2006-09-21 05:55:43 · answer #4 · answered by Anand 2 · 0 0

Let first number = x, let second number = x + 1, let third number = x + 2.
x + (x + 1) + (x + 2) = 63
3x + 3 = 63 (Subtract 3 from each side)
3x = 60 (Divide both sides by 3)
x = 20
The numbers are 20, 21, and 22.
QED

2006-09-21 07:29:42 · answer #5 · answered by CSUFGrad2006 5 · 0 0

20, 21 and 22

2006-09-21 03:27:32 · answer #6 · answered by Jemima 3 · 0 0

x +(x+1)+(x+2) = 63
x+3 =63
x= 63-3. =60=3x
x=20.
20, 21,23 are three successive numbers whose sum is 63.

2006-09-21 03:33:07 · answer #7 · answered by J.SWAMY I ఇ జ స్వామి 7 · 0 0

X + (X + 1) + (X + 2) = 60

X + X + X = 60 - 1 - 2

3X = 60

X = 20

20 + 21 + 22 = 63

I hope I explained it - better than just giving you the answer.

2006-09-21 03:29:46 · answer #8 · answered by eeaglenest 3 · 0 1

x+(x+1)+(x+2)=63
3x+3=63
3x=60
x=20
x+1=21
x+2=22
So the consecutive integer series is 20,21 & 22.

2006-09-21 03:58:55 · answer #9 · answered by miyuki & kyojin 7 · 1 0

Let one number be x.
Other two number will be x+1, x+2
According to the question,
x+x+1+x+2=63
3x+3=63
3x=60
x=20
Therefore, one number = 20
Other two numbers are 21,22.

2006-09-21 03:33:39 · answer #10 · answered by noesis 2 · 0 0

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