This is a trivia question
2006-09-21 02:17:18 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
1.[2x^2+3x-6]
=[-3+/-rt(9+48)]/4
=[-3+/-rt(57)]/4
2.2y^2+y-1=2y^2+2y-y-1
=2y(y+1)-1(y+1)
=(2y-1)(y-1)
3.4x^2-3x-3=4x^2-4x+3x-3
=4x(x-1)+1(x-1)
=(x-1)(4x+1)
2006-09-21 03:00:12 · answer #1 · answered by raj 7 · 0⤊ 0⤋
If you factor all of them together it is: 12x+5y-10
2006-09-21 02:23:05 · answer #2 · answered by yummymummy 3 · 0⤊ 0⤋
Did you try to solve the problem yourself? Where did you get stuck?
2006-09-21 02:31:34 · answer #3 · answered by Rajesh Kochhar 6 · 0⤊ 0⤋
[(2x+5.275)(2x-2.275)] / [(2y-0.732)(2y+2.732)] for the first one...
[(2x-1.1375)(2x+2.6375)] for the second...
needless to say, the terms are rounded.....
2006-09-21 02:54:08 · answer #4 · answered by cmangell 1 · 0⤊ 0⤋
I was done with math years ago....sorry.
2006-09-21 02:25:39 · answer #5 · answered by hh 4 · 0⤊ 0⤋