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formula please not just a figure !

2006-09-20 17:50:03 · 8 answers · asked by sorbitrate_trois 2 in Science & Mathematics Mathematics

8 answers

20 ( square root of (12^2 + 16^2) )

2006-09-20 17:52:43 · answer #1 · answered by curio 3 · 0 0

It is a 3 - 4 - 5 triangle so the sides will actually be
12 - 16 - 20 (20 being the diagonal)

2006-09-20 18:06:04 · answer #2 · answered by Stewart H 4 · 0 0

Do you know the Hypotenuse thingy? or something similar to that

lets make 12 = A and 16 = B and the diagonal = C

in this theorem

C^2, C square = A square + B square

So add up A square and B square, and the root of the answer is C - the diagonal length.

Forgotten the name of the theorem.
I haven't practice math for quite a while, I'm currently studying business where maths are for the purpose of counting money, profit and loss.

2006-09-20 22:32:27 · answer #3 · answered by marionette_presto 3 · 0 0

Use the Pythagorean theorem a^2 + b^2=c^2 So you put it 16^2 +12^2=c^2. Solve from there.

2006-09-20 17:52:49 · answer #4 · answered by MateoFalcone 4 · 0 0

First, please be clear that once you mention a rectangle, you do nto need to give the length and breadth twice. it is understood that the opposite sides are equal.

Use pythagoras theorem to calculate the diagonal.
diagonal ^2=16^2 + 12^2
diagonal^2 = 256+ 144 = 400
diagonal = sq.root of 400 = 20

2006-09-20 22:19:58 · answer #5 · answered by cooldude 3 · 0 0

Either diagonal of a rectangle is the hypotenuse of a right triangle with base = width and height = length (and vice versa).
Let:
a=width
b=length
c=diagonal
Then
c^2=a^2+b^2
c=sqrt(a^2+b^2)

2006-09-20 18:00:50 · answer #6 · answered by Helmut 7 · 0 0

Do a u du substitution. enable u = lnx. Then du = (a million/x)dx So, with changing the barriers into words of u, the required is now i nt(u^2du) from ln12 to ln16. You get (u^3)/3 from ln12 to ln16. So your answer is [(ln16)^3]/3-[(ln12)^3]/3

2016-12-12 12:05:46 · answer #7 · answered by Anonymous · 0 0

use the Pythagorean theorem

2006-09-20 17:51:23 · answer #8 · answered by Anonymous · 0 0

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