20 ( square root of (12^2 + 16^2) )
2006-09-20 17:52:43
·
answer #1
·
answered by curio 3
·
0⤊
0⤋
It is a 3 - 4 - 5 triangle so the sides will actually be
12 - 16 - 20 (20 being the diagonal)
2006-09-20 18:06:04
·
answer #2
·
answered by Stewart H 4
·
0⤊
0⤋
Do you know the Hypotenuse thingy? or something similar to that
lets make 12 = A and 16 = B and the diagonal = C
in this theorem
C^2, C square = A square + B square
So add up A square and B square, and the root of the answer is C - the diagonal length.
Forgotten the name of the theorem.
I haven't practice math for quite a while, I'm currently studying business where maths are for the purpose of counting money, profit and loss.
2006-09-20 22:32:27
·
answer #3
·
answered by marionette_presto 3
·
0⤊
0⤋
Use the Pythagorean theorem a^2 + b^2=c^2 So you put it 16^2 +12^2=c^2. Solve from there.
2006-09-20 17:52:49
·
answer #4
·
answered by MateoFalcone 4
·
0⤊
0⤋
First, please be clear that once you mention a rectangle, you do nto need to give the length and breadth twice. it is understood that the opposite sides are equal.
Use pythagoras theorem to calculate the diagonal.
diagonal ^2=16^2 + 12^2
diagonal^2 = 256+ 144 = 400
diagonal = sq.root of 400 = 20
2006-09-20 22:19:58
·
answer #5
·
answered by cooldude 3
·
0⤊
0⤋
Either diagonal of a rectangle is the hypotenuse of a right triangle with base = width and height = length (and vice versa).
Let:
a=width
b=length
c=diagonal
Then
c^2=a^2+b^2
c=sqrt(a^2+b^2)
2006-09-20 18:00:50
·
answer #6
·
answered by Helmut 7
·
0⤊
0⤋
Do a u du substitution. enable u = lnx. Then du = (a million/x)dx So, with changing the barriers into words of u, the required is now i nt(u^2du) from ln12 to ln16. You get (u^3)/3 from ln12 to ln16. So your answer is [(ln16)^3]/3-[(ln12)^3]/3
2016-12-12 12:05:46
·
answer #7
·
answered by Anonymous
·
0⤊
0⤋
use the Pythagorean theorem
2006-09-20 17:51:23
·
answer #8
·
answered by Anonymous
·
0⤊
0⤋