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decide whether the following is an expression an equation or inequality

2006-09-20 16:40:08 · 24 answers · asked by moeshine5 1 in Education & Reference Homework Help

24 answers

it is an equation as the LHS is given as equal to the RHS

2006-09-20 16:41:31 · answer #1 · answered by raj 7 · 0 0

Equation

2006-09-24 06:43:54 · answer #2 · answered by Anonymous · 0 0

That is an equation because there is an equal sign. An inequality doesn't have an equal sign but has either a "< or >"
Good luck!

2006-09-20 16:42:48 · answer #3 · answered by Taylor S 2 · 0 0

Equation definitely

2006-09-20 16:42:59 · answer #4 · answered by TheTechKid 3 · 0 1

It is an expression because it has more than one term, and it is an equation because it has an "=" sign.
it is not an inequality because there is no "<", or ">" or others like that.

in this equation, x=0

2006-09-20 16:47:11 · answer #5 · answered by smartman_06 3 · 0 0

That is a Algebraic expression. 5 would equal 0.
look : 5 times 0 equals 0 .
0 + 9 equals 9 .
9 equals nine.

2006-09-20 16:44:39 · answer #6 · answered by chibi_alchemist_edd 1 · 0 0

its an expression. substitute x = 0 and proceed. YOu will find that the right hand side of the equation matches the left hand side. this is the only value for x which satisifies that expression

2006-09-20 16:51:23 · answer #7 · answered by ultimatum 2 · 0 0

it's an expression of inequality , unless you put zero (0) in for x. Then it can be an equality

2006-09-20 16:48:52 · answer #8 · answered by island girl 2 · 0 0

equation. because there are two sides and you are solving for an unknown number. need the answer, x= 0

2006-09-20 16:47:04 · answer #9 · answered by recycle NYC! 3 · 0 0

cope with the inequality sign as though it have been an equivalent sign. 13.) 5x>2x+9 combine like words -2x -2x 3x>9 divide by 14.) -3x+3>9 combine like words -3x>6 divide by x>-2 with a unfavourable answer, swap the inequality sign around. 15.) 4x-5>2x+3 combine like words 2x>8 divide by

2016-10-17 09:08:10 · answer #10 · answered by Anonymous · 0 0

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